Question

\( \frac{3 \tan 315^{\circ} \sin 225^{\circ} \sin 120^{\circ}}{\cos 315^{\circ} \cos 210^{\circ}} \)

Ask by Ramirez George. in South Africa
Mar 09,2025

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Tutor-Verified Answer

Answer

The value of the expression is \(-3\).

Solution

1. Evaluate each trigonometric function: - \( \tan 315^\circ \): \(315^\circ = 360^\circ - 45^\circ\), so \(\tan 315^\circ = -\tan 45^\circ = -1\). - \( \sin 225^\circ \): \(225^\circ = 180^\circ + 45^\circ\), so \(\sin 225^\circ = -\sin 45^\circ = -\frac{\sqrt{2}}{2}\). - \( \sin 120^\circ \): \(120^\circ = 180^\circ - 60^\circ\), so \(\sin 120^\circ = \sin 60^\circ = \frac{\sqrt{3}}{2}\). - \( \cos 315^\circ \): \(315^\circ = 360^\circ - 45^\circ\), so \(\cos 315^\circ = \cos 45^\circ = \frac{\sqrt{2}}{2}\). - \( \cos 210^\circ \): \(210^\circ = 180^\circ + 30^\circ\), so \(\cos 210^\circ = -\cos 30^\circ = -\frac{\sqrt{3}}{2}\). 2. Substitute these values into the expression: \[ \frac{3 \tan 315^\circ \sin 225^\circ \sin 120^\circ}{\cos 315^\circ \cos 210^\circ} = \frac{3 \cdot (-1) \cdot \left(-\frac{\sqrt{2}}{2}\right) \cdot \frac{\sqrt{3}}{2}}{\frac{\sqrt{2}}{2} \cdot \left(-\frac{\sqrt{3}}{2}\right)} \] 3. Simplify the numerator: \[ 3 \cdot (-1) \cdot \left(-\frac{\sqrt{2}}{2}\right) \cdot \frac{\sqrt{3}}{2} = 3 \cdot \frac{\sqrt{2}}{2} \cdot \frac{\sqrt{3}}{2} = \frac{3\sqrt{6}}{4} \] 4. Simplify the denominator: \[ \frac{\sqrt{2}}{2} \cdot \left(-\frac{\sqrt{3}}{2}\right) = -\frac{\sqrt{6}}{4} \] 5. Form the complete fraction: \[ \frac{\frac{3\sqrt{6}}{4}}{-\frac{\sqrt{6}}{4}} = \frac{3\sqrt{6}}{4} \times \frac{-4}{\sqrt{6}} = -3 \] Thus, the value of the expression is \(-3\).

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Bonus Knowledge

To simplify the expression \( \frac{3 \tan 315^{\circ} \sin 225^{\circ} \sin 120^{\circ}}{\cos 315^{\circ} \cos 210^{\circ}} \), we start by evaluating each trigonometric function: 1. **\( \tan 315^{\circ} \)**: - \( \tan 315^{\circ} = \tan(-45^{\circ}) = -1 \). 2. **\( \sin 225^{\circ} \)**: - \( \sin 225^{\circ} = \sin(180^{\circ} + 45^{\circ}) = -\frac{\sqrt{2}}{2} \). 3. **\( \sin 120^{\circ} \)**: - \( \sin 120^{\circ} = \sin(90^{\circ} + 30^{\circ}) = \frac{\sqrt{3}}{2} \). 4. **\( \cos 315^{\circ} \)**: - \( \cos 315^{\circ} = \cos(-45^{\circ}) = \frac{\sqrt{2}}{2} \). 5. **\( \cos 210^{\circ} \)**: - \( \cos 210^{\circ} = \cos(180^{\circ} + 30^{\circ}) = -\frac{\sqrt{3}}{2} \). Now substitute these values into the expression: \[ \frac{3 \cdot (-1) \cdot \left(-\frac{\sqrt{2}}{2}\right) \cdot \left(\frac{\sqrt{3}}{2}\right)}{\left(\frac{\sqrt{2}}{2}\right) \cdot \left(-\frac{\sqrt{3}}{2}\right)}. \] This simplifies to: \[ \frac{3 \cdot \frac{\sqrt{2}}{2} \cdot \frac{\sqrt{3}}{2}}{\left(\frac{\sqrt{2}}{2}\right) \cdot \left(-\frac{\sqrt{3}}{2}\right)} = \frac{3 \cdot \frac{\sqrt{6}}{4}}{-\frac{\sqrt{6}}{4}}. \] The \(\frac{\sqrt{6}}{4}\) terms cancel out, leading to: \[ 3 \cdot (-1) = -3. \] Thus, the final result of the expression is: \[ \boxed{-3}. \]

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