Question
How many protons, neutrons and electrons are there in a neutral atom of the isotope represented by: \( { }_{7}^{14} \mathrm{~N} \) protons: neutrons: electrons:
Ask by Higgins Tyler. in South Africa
Feb 25,2025
Upstudy AI Solution
Tutor-Verified Answer
Answer
In the neutral atom of ¹⁴N:
- Protons: 7
- Neutrons: 7
- Electrons: 7
Solution
For the neutral atom represented by ₇¹⁴N:
• Protons: The atomic number is 7, so there are 7 protons.
• Neutrons: The mass number is 14. Since mass number = protons + neutrons, there are 14 - 7 = 7 neutrons.
• Electrons: Since the atom is neutral, the number of electrons equals the number of protons, which is 7 electrons.
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Simplify this solution The Deep Dive
In the isotope \( { }_{7}^{14} \mathrm{~N} \), the number 7 represents the atomic number, indicating that there are 7 protons in a neutral nitrogen atom. Since this atom is neutral, it also has 7 electrons, balancing the positive charge of the protons. To find the number of neutrons, you subtract the atomic number from the mass number (14 - 7), resulting in 7 neutrons. So, in summary: protons: 7 neutrons: 7 electrons: 7
