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FION 2 Find the HCF of \( 24 x^{3} y z^{4} ; 30 x^{2} y^{2} z^{3} \) and \( 36 x^{3} y^{2} z^{3} \)

Ask by Mejia Flynn. in South Africa
Mar 09,2025

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Tutor-Verified Answer

Answer

The HCF of \(24x^{3}yz^{4}\), \(30x^{2}y^{2}z^{3}\), and \(36x^{3}y^{2}z^{3}\) is \(6x^{2}yz^{3}\).

Solution

1. **Find the HCF of the numerical coefficients** - The coefficients are \(24\), \(30\), and \(36\). - Prime factorizations: - \(24 = 2^3 \times 3\) - \(30 = 2 \times 3 \times 5\) - \(36 = 2^2 \times 3^2\) - Take the minimum power of each common prime: - For \(2\): minimum power is \(2^1\). - For \(3\): minimum power is \(3^1\). - Therefore, the HCF of the coefficients is: \[ 2^1 \times 3^1 = 6 \] 2. **Find the HCF for the variables** - For \(x\): - Exponents: \(3\) (from \(x^3\)), \(2\) (from \(x^2\)), and \(3\) (from \(x^3\)). - Minimum exponent is \(2\), so the common factor is \(x^2\). - For \(y\): - Exponents: \(1\) (from \(y\)), \(2\) (from \(y^2\)), and \(2\) (from \(y^2\)). - Minimum exponent is \(1\), so the common factor is \(y\). - For \(z\): - Exponents: \(4\) (from \(z^4\)), \(3\) (from \(z^3\)), and \(3\) (from \(z^3\)). - Minimum exponent is \(3\), so the common factor is \(z^3\). 3. **Combine the results** The HCF of the three expressions is: \[ 6 x^2 y z^3 \]

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To find the HCF (Highest Common Factor) of the given expressions, we need to break down each term into its prime factors and the variables: 1. **For \( 24 x^{3} y z^{4} \)**: - 24 can be factored as \( 2^3 \times 3^1 \). - So, \( 24 x^{3} y z^{4} = 2^3 \times 3^1 \times x^{3} \times y^{1} \times z^{4} \). 2. **For \( 30 x^{2} y^{2} z^{3} \)**: - 30 can be factored as \( 2^1 \times 3^1 \times 5^1 \). - So, \( 30 x^{2} y^{2} z^{3} = 2^1 \times 3^1 \times 5^1 \times x^{2} \times y^{2} \times z^{3} \). 3. **For \( 36 x^{3} y^{2} z^{3} \)**: - 36 can be factored as \( 2^2 \times 3^2 \). - So, \( 36 x^{3} y^{2} z^{3} = 2^2 \times 3^2 \times x^{3} \times y^{2} \times z^{3} \). Now we find the HCF by taking the lowest power of all prime factors and variables: - For \( 2 \): The lowest power is \( 2^1 \). - For \( 3 \): The lowest power is \( 3^1 \). - For \( x \): The lowest power is \( x^{2} \). - For \( y \): The lowest power is \( y^{1} \). - For \( z \): The lowest power is \( z^{3} \). Putting this all together, we get: \[ HCF = 2^1 \times 3^1 \times x^{2} \times y^{1} \times z^{3} = 6 x^{2} y z^{3} \] So, the HCF of \( 24 x^{3} y z^{4} \), \( 30 x^{2} y^{2} z^{3} \), and \( 36 x^{3} y^{2} z^{3} \) is \( 6 x^{2} y z^{3} \).

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