Pregunta
upstudy study bank question image url

FION 2 Find the HCF of \( 24 x^{3} y z^{4} ; 30 x^{2} y^{2} z^{3} \) and \( 36 x^{3} y^{2} z^{3} \)

Ask by Mejia Flynn. in South Africa
Mar 09,2025

Solución de inteligencia artificial de Upstudy

Respuesta verificada por el tutor

Responder

The HCF of \(24x^{3}yz^{4}\), \(30x^{2}y^{2}z^{3}\), and \(36x^{3}y^{2}z^{3}\) is \(6x^{2}yz^{3}\).

Solución

1. **Find the HCF of the numerical coefficients** - The coefficients are \(24\), \(30\), and \(36\). - Prime factorizations: - \(24 = 2^3 \times 3\) - \(30 = 2 \times 3 \times 5\) - \(36 = 2^2 \times 3^2\) - Take the minimum power of each common prime: - For \(2\): minimum power is \(2^1\). - For \(3\): minimum power is \(3^1\). - Therefore, the HCF of the coefficients is: \[ 2^1 \times 3^1 = 6 \] 2. **Find the HCF for the variables** - For \(x\): - Exponents: \(3\) (from \(x^3\)), \(2\) (from \(x^2\)), and \(3\) (from \(x^3\)). - Minimum exponent is \(2\), so the common factor is \(x^2\). - For \(y\): - Exponents: \(1\) (from \(y\)), \(2\) (from \(y^2\)), and \(2\) (from \(y^2\)). - Minimum exponent is \(1\), so the common factor is \(y\). - For \(z\): - Exponents: \(4\) (from \(z^4\)), \(3\) (from \(z^3\)), and \(3\) (from \(z^3\)). - Minimum exponent is \(3\), so the common factor is \(z^3\). 3. **Combine the results** The HCF of the three expressions is: \[ 6 x^2 y z^3 \]

Respondido por UpStudy AI y revisado por un tutor profesional

error msg
Explicar
Simplifique esta solución

Extra Insights

To find the HCF (Highest Common Factor) of the given expressions, we need to break down each term into its prime factors and the variables: 1. **For \( 24 x^{3} y z^{4} \)**: - 24 can be factored as \( 2^3 \times 3^1 \). - So, \( 24 x^{3} y z^{4} = 2^3 \times 3^1 \times x^{3} \times y^{1} \times z^{4} \). 2. **For \( 30 x^{2} y^{2} z^{3} \)**: - 30 can be factored as \( 2^1 \times 3^1 \times 5^1 \). - So, \( 30 x^{2} y^{2} z^{3} = 2^1 \times 3^1 \times 5^1 \times x^{2} \times y^{2} \times z^{3} \). 3. **For \( 36 x^{3} y^{2} z^{3} \)**: - 36 can be factored as \( 2^2 \times 3^2 \). - So, \( 36 x^{3} y^{2} z^{3} = 2^2 \times 3^2 \times x^{3} \times y^{2} \times z^{3} \). Now we find the HCF by taking the lowest power of all prime factors and variables: - For \( 2 \): The lowest power is \( 2^1 \). - For \( 3 \): The lowest power is \( 3^1 \). - For \( x \): The lowest power is \( x^{2} \). - For \( y \): The lowest power is \( y^{1} \). - For \( z \): The lowest power is \( z^{3} \). Putting this all together, we get: \[ HCF = 2^1 \times 3^1 \times x^{2} \times y^{1} \times z^{3} = 6 x^{2} y z^{3} \] So, the HCF of \( 24 x^{3} y z^{4} \), \( 30 x^{2} y^{2} z^{3} \), and \( 36 x^{3} y^{2} z^{3} \) is \( 6 x^{2} y z^{3} \).

preguntas relacionadas

Latest Algebra Questions

¡Prueba Premium ahora!
¡Prueba Premium y hazle a Thoth AI preguntas de matemáticas ilimitadas ahora!
Quizas mas tarde Hazte Premium
Estudiar puede ser una verdadera lucha
¿Por qué no estudiarlo en UpStudy?
Seleccione su plan a continuación
Prima

Puedes disfrutar

Empieza ahora
  • Explicaciones paso a paso
  • Tutores expertos en vivo 24/7
  • Número ilimitado de preguntas
  • Sin interrupciones
  • Acceso completo a Respuesta y Solución
  • Acceso completo al chat de PDF, al chat de UpStudy y al chat de navegación
Básico

Totalmente gratis pero limitado

  • Solución limitada
Bienvenido a ¡Estudia ahora!
Inicie sesión para continuar con el recorrido de Thoth AI Chat
Continuar con correo electrónico
O continuar con
Al hacer clic en "Iniciar sesión", acepta nuestros términos y condiciones. Términos de Uso & Política de privacidad