Use synthetic division to find the quotient. \( \frac{2 x^{3}-5 x^{2}+6 x+8}{x+2} \) \( [?] x^{2}+x+\square+\overline{x+2} \)
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To perform synthetic division of \(2x^3 - 5x^2 + 6x + 8\) by \(x + 2\), we will use \( -2 \) for synthetic division since we set the equation to zero with \(x = -2\). 1. Write down the coefficients: 2, -5, 6, 8. 2. Bring down the 2. 3. Multiply -2 by 2 to get -4 and add it to -5 to get -9. 4. Multiply -2 by -9 to get 18 and add it to 6 to get 24. 5. Finally, multiply -2 by 24 to get -48 and add it to 8 to get -40. The numbers we gathered in the process are: \(2\), \(-9\), \(24\). This means the quotient is \(2x^2 - 9x + 24\) with a remainder of \(-40\). So, \[ \frac{2x^{3}-5x^{2}+6x+8}{x+2} = 2x^{2} - 9x + 24 \quad \text{with remainder}\ -40. \] Thus, the answer is: \[ 2x^{2} - 9x + 24 + \frac{-40}{x + 2}. \]