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Graph all vertical and horizontal asymptotes of the rational function, \[ f(x)=\frac{-3}{4 x+10} \]

Ask by Hobbs Robbins. in the United States
Feb 20,2025

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Tutor-Verified Answer

Answer

The vertical asymptote is at x = -5/2 and the horizontal asymptote is at y = 0.

Solution

To find the vertical asymptote, set the denominator equal to zero:   4x + 10 = 0   4x = -10   x = -10/4 = -5/2 Thus, the vertical asymptote is the line x = -5/2. For the horizontal asymptote, note that the degree of the numerator (0, since the numerator is the constant -3) is less than the degree of the denominator (1). When the numerator's degree is less than that of the denominator, the horizontal asymptote is given by y = 0. So the horizontal asymptote is the line y = 0. In summary: • Vertical asymptote: x = -5/2 • Horizontal asymptote: y = 0 When graphing the function f(x) = (-3)/(4x + 10), draw a vertical dashed line at x = -5/2 and a horizontal dashed line at y = 0. These lines indicate the behavior of the function as it approaches values near the asymptotes.

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To find the vertical asymptote of the function \( f(x) = \frac{-3}{4x + 10} \), we set the denominator equal to zero: \[ 4x + 10 = 0 \] Solving for \( x \), we get \( 4x = -10 \) or \( x = -\frac{5}{2} \). Thus, there is a vertical asymptote at \( x = -\frac{5}{2} \). Next, to find the horizontal asymptote, we consider the degrees of the polynomial in the numerator and denominator. The degree of the numerator is 0 (a constant) while the degree of the denominator is 1 (linear). In this case, since the degree of the numerator is less than the degree of the denominator, the horizontal asymptote is at \( y = 0 \). In summary, the vertical asymptote is at \( x = -\frac{5}{2} \) and the horizontal asymptote is at \( y = 0 \).

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