Question

4.2 Find the value of the following: \( 4.2 .15^{3}+\sqrt{10000} \) \( \qquad \) \( \qquad \) \( 4.2 .2(-6)^{2} \div(-10)^{2} \) \( \qquad \) \( \qquad \) \( \qquad \)

Ask by Savage Goodwin. in South Africa
Mar 12,2025

Upstudy AI Solution

Tutor-Verified Answer

Answer

The value of the first expression is 100.014175, and the value of the second expression is 0.3024.

Solution

We begin by evaluating each expression step by step. ### 1. Evaluate \( 4.2 \cdot (0.15)^3 + \sqrt{10000} \) 1. Compute the cube of \(0.15\): \[ (0.15)^3 = 0.15 \times 0.15 \times 0.15 = 0.003375. \] 2. Multiply this result by \(4.2\): \[ 4.2 \cdot 0.003375 = 0.014175. \] 3. Compute the square root of \(10000\): \[ \sqrt{10000} = 100. \] 4. Add these results together: \[ 0.014175 + 100 = 100.014175. \] Thus, the value of the first expression is \[ 100.014175. \] ### 2. Evaluate \( 4.2 \cdot 0.2 \cdot (-6)^2 \div (-10)^2 \) 1. Multiply \(4.2\) by \(0.2\): \[ 4.2 \cdot 0.2 = 0.84. \] 2. Evaluate \((-6)^2\): \[ (-6)^2 = 36. \] 3. Evaluate \((-10)^2\): \[ (-10)^2 = 100. \] 4. Multiply \(0.84\) by \(36\): \[ 0.84 \cdot 36 = 30.24. \] 5. Divide the result by \(100\): \[ \frac{30.24}{100} = 0.3024. \] Thus, the value of the second expression is \[ 0.3024. \]

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The Deep Dive

To find the value of \( 4.2 .15^{3}+\sqrt{10000} \): First, calculate \( 15^3 \): \( 15^3 = 3375 \) Now, multiply by \( 4.2 \): \( 4.2 \times 3375 = 14175 \) Next, calculate \( \sqrt{10000} \): \( \sqrt{10000} = 100 \) Now, add the two results: \( 14175 + 100 = 14275 \) So, the value of \( 4.2 .15^{3}+\sqrt{10000} \) is \( 14275 \). Now, for \( 4.2 .2(-6)^{2} \div(-10)^{2} \): Calculate \( (-6)^2 = 36 \) and \( (-10)^2 = 100 \). Now, multiply \( 0.2 \times 36 \): \( 0.2 \times 36 = 7.2 \) Then, divide by \( 100 \): \( 7.2 \div 100 = 0.072 \) Finally, multiply by \( 4.2 \): \( 4.2 \times 0.072 = 0.3024 \) So, the value of \( 4.2 .2(-6)^{2} \div(-10)^{2} \) is \( 0.3024 \). In summary: 1. \( 4.2 .15^{3}+\sqrt{10000} = 14275 \) 2. \( 4.2 .2(-6)^{2} \div(-10)^{2} = 0.3024 \)

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