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On a certain day a cell phone store sold iphones, Samsungs and Huaweis in the ratio \( 2: 3 \) : 5 . If they sold 15 Huaweis, how many cellphones did they sell altogethe

Ask by Sullivan Washington. in South Africa
Mar 12,2025

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Answer

The store sold a total of 30 cellphones.

Solution

1. Let the constants in the ratio be represented by \( k \). Then, the number of each type of cellphone sold is: \[ \text{iPhones} = 2k,\quad \text{Samsungs} = 3k,\quad \text{Huaweis} = 5k. \] 2. Since 15 Huaweis were sold, we set up the equation: \[ 5k = 15. \] 3. Solving for \( k \): \[ k = \frac{15}{5} = 3. \] 4. The total number of cellphones sold is: \[ \text{Total} = 2k + 3k + 5k = 10k. \] 5. Substitute \( k = 3 \) into the equation: \[ \text{Total} = 10 \times 3 = 30. \] Thus, the store sold a total of \( 30 \) cellphones.

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In the given ratio of iPhones, Samsungs, and Huaweis, the parts are 2 for iPhones, 3 for Samsungs, and 5 for Huaweis. Since they sold 15 Huaweis, we can determine that one part of the ratio corresponds to 3 units (15 Huaweis / 5 parts = 3). Now, we can calculate the number of each type of cellphone sold: - iPhones: \(2 \times 3 = 6\) - Samsungs: \(3 \times 3 = 9\) - Huaweis: \(5 \times 3 = 15\) Adding these up gives us \(6 + 9 + 15 = 30\) cellphones sold in total. So, the store sold a total of 30 cellphones.

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