Suppose that the $$ x $$-intercepts of the graph of $$ y=f(x) $$ are -6 and -3 . (a) What are the $$ x $$-intercepts of the graph of $$ y=1(x+8) $$ ? The $$ x $$-intercepls of the graph of $$ y=f(x+8) $$ are (Use a comma to separate answers as needed.)

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To find the $$ x $$-intercepts of the graph of $$ y = f(x + 8) $$, we need to understand how the transformation affects the $$ x $$-intercepts of the original function $$ f(x) $$.

1. The $$ x $$-intercepts of $$ f(x) $$ are the points where $$ f(x) = 0 $$. Given that the $$ x $$-intercepts of $$ f(x) $$ are -6 and -3, we can express this as:
   $$
   f(-6) = 0 \quad \text{and} \quad f(-3) = 0
   $$

2. The transformation $$ f(x + 8) $$ shifts the graph of $$ f(x) $$ to the left by 8 units. Therefore, to find the new $$ x $$-intercepts, we set $$ x + 8 = -6 $$ and $$ x + 8 = -3 $$.

3. Solving these equations:
   - For $$ x + 8 = -6 $$:
     $$
     x = -6 - 8 = -14
     $$
   - For $$ x + 8 = -3 $$:
     $$
     x = -3 - 8 = -11
     $$

Thus, the $$ x $$-intercepts of the graph of $$ y = f(x + 8) $$ are $$ -14 $$ and $$ -11 $$.

The $$ x $$-intercepts of the graph of $$ y = f(x + 8) $$ are:
$$
-14, -11
$$
The $$ x $$-intercepts of the graph of $$ y = f(x + 8) $$ are -14 and -11.

Suppose that the \( x \)-intercepts of the graph of \( y=f(x) \) are -6 and -3 . (a) What are the \( x \)-intercepts of the graph of \( y=1(x+8) \) ? The \( x \)-intercepls of the graph of \( y=f(x+8) \) are (Use a comma to separate answers as needed.)

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