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Note that a change can be an Increase or a decrease. For an Increase, use a positive number. For a decrease, use a negative number. \( \begin{array}{l}\text { (a) A tram moved upward } 9 \text { meters per second for } 72 \text { seconds. What was the total change in the } \\ \text { tram's elevation? } \\ \text { (b) In a lab, a substance was cooled by } 20^{\circ} \mathrm{C} \text { over a period of } 10 \text { hours at a constant rate. What } \\ \text { was the change in temperature each hour? } \\ \square{ }^{\circ} \mathrm{C}\end{array} \)

Ask by Bowman Santiago. in the United States
Mar 08,2025

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Answer

- For part (a), the tram's elevation increased by 648 meters. - For part (b), the temperature decreased by 2°C each hour.

Solution

1. For part (a): - The tram’s speed is \(9 \, \text{meters per second}\) and it traveled for \(72\) seconds. - The total change in elevation is calculated as: \[ 9 \times 72 = 648 \, \text{meters.} \] - Since the tram moved upward, the change is positive: \(+648\) meters. 2. For part (b): - The temperature decreased by \(20^\circ \text{C}\) over \(10\) hours. - The change in temperature per hour is given by: \[ \frac{-20}{10} = -2^\circ \text{C per hour.} \] - The negative sign indicates a decrease in temperature.

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The total change in the tram's elevation can be found by multiplying its speed by the time it moved. So, if the tram moved upward at 9 meters per second for 72 seconds, the total change in elevation is \(9 \times 72 = 648\) meters. Therefore, the total change in elevation is +648 meters. For the cooling substance, when it cooled down by 20°C over 10 hours, you can determine the hourly change by dividing the total change by the time taken. Hence, the change in temperature each hour is \( \frac{-20}{10} = -2 \) degrees Celsius. So, the change in temperature per hour is -2°C.

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