Solve the following. \( \begin{array}{l}\text { 16. } 8 x+3=2 x-9\end{array} \begin{array}{l}\text { 17. } 4(x-3)+2(x+1)=14\end{array} \)
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Let's solve the equations one by one! For the first equation: \[ 8x + 3 = 2x - 9 \] 1. Subtract \(2x\) from both sides: \[ 8x - 2x + 3 = -9 \] \[ 6x + 3 = -9 \] 2. Now, subtract \(3\) from both sides: \[ 6x = -9 - 3 \] \[ 6x = -12 \] 3. Finally, divide both sides by \(6\): \[ x = -2 \] Now for the second equation: \[ 4(x - 3) + 2(x + 1) = 14 \] 1. Distribute \(4\) and \(2\): \[ 4x - 12 + 2x + 2 = 14 \] 2. Combine like terms: \[ 6x - 10 = 14 \] 3. Add \(10\) to both sides: \[ 6x = 24 \] 4. Divide by \(6\): \[ x = 4 \] So, the solutions are \(x = -2\) for the first equation and \(x = 4\) for the second equation!