The angle of inclination from the base of skyscraper A to the top of skyscraper B is approximately \( 10.7^{\circ} \). If skyscraper B is 1433 fee Assume the bases of the two buildings are at the same elevation. The distance from skyscraper A to skyscraper B is (Round to two decimal places as needed.)

Given: - The angle of inclination from the base of skyscraper A to the top of skyscraper B is \( 10.7^{\circ} \). - The height of skyscraper B is 1433 feet. Let's denote: - The distance from skyscraper A to skyscraper B as \( d \) feet. We can use trigonometry to solve this problem. The tangent of the angle of inclination is equal to the ratio of the opposite side (height of skyscraper B) to the adjacent side (distance from skyscraper A to skyscraper B). So, we have: \[ \tan(10.7^{\circ}) = \frac{1433}{d} \] We can solve for \( d \) by rearranging the equation and calculating the value. Calculate the value by following steps: - step0: Calculate: \(\tan\left(10.7\right)\) The tangent of \(10.7^{\circ}\) is approximately 3.284141. Now, we can solve for the distance \(d\) using the equation: \[ 3.284141 = \frac{1433}{d} \] Let's solve for \(d\). Calculate the value by following steps: - step0: Calculate: \(\frac{1433}{3.284141}\) - step1: Convert the expressions: \(\frac{1433}{\frac{3284141}{1000000}}\) - step2: Multiply by the reciprocal: \(1433\times \frac{1000000}{3284141}\) - step3: Multiply: \(\frac{1433\times 1000000}{3284141}\) - step4: Multiply: \(\frac{1433000000}{3284141}\) The distance from skyscraper A to skyscraper B is approximately 436.34 feet.