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Let \( Z \sim N(0,1) \). Accurate to 4 decimal places, evaluate \( P(-0.37 \leq Z \leq-0.07) \) 0.3557 0.1164 0.8836 0.4721 None of the above.

Ask by Frank Gardner. in the United States
Mar 09,2025

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Answer

The probability \( P(-0.37 \leq Z \leq -0.07) \) is approximately 0.1164.

Solution

We are to evaluate \[ P(-0.37 \leq Z \leq -0.07) \] for \( Z \sim N(0,1) \). **Step 1. Express the probability in terms of the CDF** The probability can be written as \[ P(-0.37 \leq Z \leq -0.07) = \Phi(-0.07) - \Phi(-0.37) \] where \(\Phi(z)\) is the cumulative distribution function of the standard normal distribution. **Step 2. Use the symmetry property of the standard normal distribution** Recall the property \[ \Phi(-z) = 1 - \Phi(z). \] Using this: \[ \Phi(-0.07) = 1 - \Phi(0.07) \] \[ \Phi(-0.37) = 1 - \Phi(0.37). \] **Step 3. Substitute and simplify** Substitute in the original expression: \[ P(-0.37 \leq Z \leq -0.07) = \bigl[1 - \Phi(0.07)\bigr] - \bigl[1 - \Phi(0.37)\bigr] = \Phi(0.37) - \Phi(0.07). \] **Step 4. Look up the standard normal values** Using a standard normal table or calculator: \[ \Phi(0.07) \approx 0.5279, \] \[ \Phi(0.37) \approx 0.6443. \] **Step 5. Compute the difference** Now subtract: \[ P(-0.37 \leq Z \leq -0.07) \approx 0.6443 - 0.5279 = 0.1164. \] Thus, accurate to 4 decimal places, the probability is \( \boxed{0.1164} \).

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To find \( P(-0.37 \leq Z \leq -0.07) \), we can use the cumulative distribution function (CDF) for the standard normal distribution, which is represented as \( \Phi(z) \). First, we need to determine \( \Phi(-0.07) \) and \( \Phi(-0.37) \): 1. Using standard normal distribution tables or software: - \( \Phi(-0.07) \approx 0.4721 \) - \( \Phi(-0.37) \approx 0.3557 \) Now, we calculate the probability: \[ P(-0.37 \leq Z \leq -0.07) = \Phi(-0.07) - \Phi(-0.37) \] Substituting the values we found: \[ P(-0.37 \leq Z \leq -0.07) = 0.4721 - 0.3557 \approx 0.1164 \] Thus, the correct answer is **0.1164**.

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