Let \( Z \sim N(0,1) \). Accurate to 4 decimal places, evaluate \( P(-0.37 \leq Z \leq-0.07) \) 0.3557 0.1164 0.8836 0.4721 None of the above.
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To find \( P(-0.37 \leq Z \leq -0.07) \), we can use the cumulative distribution function (CDF) for the standard normal distribution, which is represented as \( \Phi(z) \). First, we need to determine \( \Phi(-0.07) \) and \( \Phi(-0.37) \): 1. Using standard normal distribution tables or software: - \( \Phi(-0.07) \approx 0.4721 \) - \( \Phi(-0.37) \approx 0.3557 \) Now, we calculate the probability: \[ P(-0.37 \leq Z \leq -0.07) = \Phi(-0.07) - \Phi(-0.37) \] Substituting the values we found: \[ P(-0.37 \leq Z \leq -0.07) = 0.4721 - 0.3557 \approx 0.1164 \] Thus, the correct answer is **0.1164**.