Answer
| Function | Domain | Range |
|-------------------------|-------------------|-----------------|
| \( y = -4x^2 \) | \( (-\infty, \infty) \) | \( (-\infty, 0] \) |
| \( f(x) = 3x^2 \) | \( (-\infty, \infty) \) | \( [0, \infty) \) |
| \( f(x) = \frac{2}{3}x^2 \) | \( (-\infty, \infty) \) | \( [0, \infty) \) |
| \( y(x) = 1.5x^2 \) | \( (-\infty, \infty) \) | \( [0, \infty) \) |
| \( y = -\frac{1}{3}x^2 \) | \( (-\infty, \infty) \) | \( (-\infty, 0] \) |
Solution
Let's analyze each function one by one, graph them, and identify their domains and ranges.
### 10. \( y = -4x^2 \)
**Graph:** This is a downward-opening parabola with its vertex at the origin (0, 0).
**Domain:** The domain of any quadratic function is all real numbers, so:
\[ \text{Domain: } (-\infty, \infty) \]
**Range:** Since the parabola opens downwards, the maximum value is at the vertex (0, 0), and it goes downwards indefinitely:
\[ \text{Range: } (-\infty, 0] \]
---
### 12. \( f(x) = 3x^2 \)
**Graph:** This is an upward-opening parabola with its vertex at the origin (0, 0).
**Domain:** The domain is all real numbers:
\[ \text{Domain: } (-\infty, \infty) \]
**Range:** Since the parabola opens upwards, the minimum value is at the vertex (0, 0), and it goes upwards indefinitely:
\[ \text{Range: } [0, \infty) \]
---
### 13. \( f(x) = \frac{2}{3}x^2 \)
**Graph:** This is also an upward-opening parabola with its vertex at the origin (0, 0), but it is wider than the previous one.
**Domain:** The domain is all real numbers:
\[ \text{Domain: } (-\infty, \infty) \]
**Range:** The minimum value is at the vertex (0, 0), and it goes upwards indefinitely:
\[ \text{Range: } [0, \infty) \]
---
### 14. \( y(x) = 1.5x^2 \)
**Graph:** This is another upward-opening parabola with its vertex at the origin (0, 0).
**Domain:** The domain is all real numbers:
\[ \text{Domain: } (-\infty, \infty) \]
**Range:** The minimum value is at the vertex (0, 0), and it goes upwards indefinitely:
\[ \text{Range: } [0, \infty) \]
---
### 15. \( y = -\frac{1}{3}x^2 \)
**Graph:** This is a downward-opening parabola with its vertex at the origin (0, 0), but it is wider than the first function.
**Domain:** The domain is all real numbers:
\[ \text{Domain: } (-\infty, \infty) \]
**Range:** Since the parabola opens downwards, the maximum value is at the vertex (0, 0), and it goes downwards indefinitely:
\[ \text{Range: } (-\infty, 0] \]
---
### Summary of Domains and Ranges
| Function | Domain | Range |
|-------------------------|-------------------|-----------------|
| \( y = -4x^2 \) | \( (-\infty, \infty) \) | \( (-\infty, 0] \) |
| \( f(x) = 3x^2 \) | \( (-\infty, \infty) \) | \( [0, \infty) \) |
| \( f(x) = \frac{2}{3}x^2 \) | \( (-\infty, \infty) \) | \( [0, \infty) \) |
| \( y(x) = 1.5x^2 \) | \( (-\infty, \infty) \) | \( [0, \infty) \) |
| \( y = -\frac{1}{3}x^2 \) | \( (-\infty, \infty) \) | \( (-\infty, 0] \) |
These functions are all parabolas, and their domains are all real numbers, while their ranges depend on whether they open upwards or downwards.
Answered by UpStudy AI and reviewed by a Professional Tutor
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Explain
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Simplify this solution