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Describe the error in the problem \( x^{3}-25 x=0 \) \( x^{3}=25 x \) \( x^{2}=25 \) \( x= \pm 5 \)

Ask by Mccoy Bowers. in the United States
Feb 21,2025

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The error is in the step where \( x^{3} = 25x \) is incorrectly simplified to \( x^{2} = 25 \). The correct approach is to factor out \( x \), resulting in \( x(x^{2} - 25) = 0 \), which gives solutions \( x = 0 \), \( x = 5 \), and \( x = -5 \).

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The error in the problem occurs in the step where \( x^{3} = 25x \) is transformed to \( x^{2} = 25 \). In fact, the correct manipulation involves factoring \( x \) out from the original equation: \( x^3 - 25x = 0 \), which becomes \( x(x^2 - 25) = 0 \). Thus, one must recognize that \( x = 0 \) is also a solution in addition to \( x = \pm 5 \). To solve the equation correctly, we start with \( x(x^2 - 25) = 0 \). This indicates three possible solutions: \( x = 0 \), \( x - 5 = 0 \) (which gives \( x = 5 \)), and \( x + 5 = 0 \) (which gives \( x = -5 \)). Hence, the complete solution set includes \( x = 0, 5, -5 \).

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