Answer
**Summary:**
1. **Conjecture for \( r^{n} \) and \( S_{n} \) as \( n \rightarrow \infty \):**
- If \( |r| < 1 \), the sum \( S_n \) converges to \( \frac{a}{1 - r} \).
- If \( |r| \geq 1 \), the sum \( S_n \) diverges.
2. **Sum of Geometric Series when \( r=1 \):**
- \( S_n = na \)
3. **Conjecture for \( r = -1 \):**
- The sequence is divergent because it alternates and does not approach a single value.
4. **Possible Values of \( r \) (\( -1 < r < 1 \)):**
- 0.5, -0.5, 0.9
5. **Areas of Paper Pieces:**
- First piece: 148.5 cm²
- Second piece: 74.25 cm²
- Next three pieces: 37.31 cm², 18.66 cm², 9.33 cm²
Solution
Let's break down the problem step by step.
### 1.3.2 Conjecture Regarding \( r^{n} \) and \( S_{n} \) as \( n \rightarrow \infty \)
In a geometric series, the sum \( S_n \) is given by:
\[
S_n = a + ar + ar^2 + \ldots + ar^{n-1}
\]
The formula for the sum of the first \( n \) terms of a geometric series is:
\[
S_n = a \frac{1 - r^n}{1 - r} \quad \text{if } r \neq 1
\]
As \( n \rightarrow \infty \):
- If \( |r| < 1 \), then \( r^n \rightarrow 0 \), and thus \( S_n \rightarrow \frac{a}{1 - r} \).
- If \( |r| > 1 \), then \( r^n \rightarrow \infty \), and thus \( S_n \) diverges.
- If \( r = 1 \), then \( S_n = na \), which also diverges as \( n \rightarrow \infty \).
**Conjecture**: As \( n \rightarrow \infty \):
- If \( |r| < 1 \), \( S_n \) converges to \( \frac{a}{1 - r} \).
- If \( |r| \geq 1 \), \( S_n \) diverges.
### 1.4 CASE 3: \( r=1 \)
#### 1.4.1 Sum of the Geometric Series when \( r=1 \)
When \( r = 1 \):
\[
S_n = a + a + a + \ldots + a \quad (n \text{ terms}) = na
\]
Thus, the sum of the geometric series is:
\[
S_n = na
\]
#### 1.4.2 Conjecture Regarding \( r = -1 \)
When \( r = -1 \):
\[
S_n = a - a + a - a + \ldots
\]
The terms alternate between \( a \) and \( -a \). The sum depends on whether \( n \) is even or odd:
- If \( n \) is even, \( S_n = 0 \).
- If \( n \) is odd, \( S_n = a \).
**Conjecture**: The sequence is divergent because it does not approach a single value as \( n \rightarrow \infty \).
### 1.6.1 Possible Values of \( r \) such that \( -1 < r < 1 \)
Three possible values of \( r \) in the interval \( -1 < r < 1 \) could be:
1. \( r = 0.5 \)
2. \( r = -0.5 \)
3. \( r = 0.9 \)
### 1.6.5 and 1.6.6 Areas of Paper Pieces
1. **Step 4**: The first piece of paper has an area of \( \frac{1}{2} \) the area of A4. The area of A4 is approximately \( 0.297 \, m^2 \) or \( 297 \, cm^2 \). Thus, the area of the first piece is:
\[
\text{Area}_1 = \frac{1}{2} \times 297 \, cm^2 = 148.5 \, cm^2
\]
2. **Step 5**: The second piece of paper has an area of \( \frac{1}{4} \) the area of A4:
\[
\text{Area}_2 = \frac{1}{4} \times 297 \, cm^2 = 74.25 \, cm^2
\]
3. **Next Three Areas**: Continuing this pattern, the areas of the next three pieces of paper would be:
- Third piece: \( \frac{1}{8} \times 297 \, cm^2 = 37.3125 \, cm^2 \)
- Fourth piece: \( \frac{1}{16} \times 297 \, cm^2 = 18.65625 \, cm^2 \)
- Fifth piece: \( \frac{1}{32} \times 297 \, cm^2 = 9.328125 \, cm^2 \)
Thus, the areas of the next three pieces of paper are approximately:
1. \( 37.31 \, cm^2 \)
2. \( 18.66 \, cm^2 \)
3. \( 9.33 \, cm^2 \)
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