Question
upstudy study bank question image url

4 1.3.2 Make a conjecture with regard to \( r^{n} \) and \( S_{,} \)as \( n \rightarrow \infty \) (2) 1.4 CASE 3: \( r=1 \) 1.4.1 What is the sum of the geometric series \[ S_{-}=a+a r+a r^{2}+\ldots a r^{n-1} \text { if } r=1 ? \] 1.4.2 Make a conjecture with regard to \( r^{\prime \prime} \) and \( S_{n} \) as \( n \rightarrow \infty \) \[ S_{n}=a+a r+a r^{2}+\ldots a r^{n-1} \text { if } r=-1 ? \] i.e. is the sequence divergent or convergent? 1.6.1 Write THREE possible values of \( r \) such that \( -1
Ask by Reed Lee. in South Africa
Feb 26,2025

Upstudy AI Solution

Tutor-Verified Answer

Answer

**Summary:** 1. **Conjecture for \( r^{n} \) and \( S_{n} \) as \( n \rightarrow \infty \):** - If \( |r| < 1 \), the sum \( S_n \) converges to \( \frac{a}{1 - r} \). - If \( |r| \geq 1 \), the sum \( S_n \) diverges. 2. **Sum of Geometric Series when \( r=1 \):** - \( S_n = na \) 3. **Conjecture for \( r = -1 \):** - The sequence is divergent because it alternates and does not approach a single value. 4. **Possible Values of \( r \) (\( -1 < r < 1 \)):** - 0.5, -0.5, 0.9 5. **Areas of Paper Pieces:** - First piece: 148.5 cm² - Second piece: 74.25 cm² - Next three pieces: 37.31 cm², 18.66 cm², 9.33 cm²

Solution

Let's break down the problem step by step. ### 1.3.2 Conjecture Regarding \( r^{n} \) and \( S_{n} \) as \( n \rightarrow \infty \) In a geometric series, the sum \( S_n \) is given by: \[ S_n = a + ar + ar^2 + \ldots + ar^{n-1} \] The formula for the sum of the first \( n \) terms of a geometric series is: \[ S_n = a \frac{1 - r^n}{1 - r} \quad \text{if } r \neq 1 \] As \( n \rightarrow \infty \): - If \( |r| < 1 \), then \( r^n \rightarrow 0 \), and thus \( S_n \rightarrow \frac{a}{1 - r} \). - If \( |r| > 1 \), then \( r^n \rightarrow \infty \), and thus \( S_n \) diverges. - If \( r = 1 \), then \( S_n = na \), which also diverges as \( n \rightarrow \infty \). **Conjecture**: As \( n \rightarrow \infty \): - If \( |r| < 1 \), \( S_n \) converges to \( \frac{a}{1 - r} \). - If \( |r| \geq 1 \), \( S_n \) diverges. ### 1.4 CASE 3: \( r=1 \) #### 1.4.1 Sum of the Geometric Series when \( r=1 \) When \( r = 1 \): \[ S_n = a + a + a + \ldots + a \quad (n \text{ terms}) = na \] Thus, the sum of the geometric series is: \[ S_n = na \] #### 1.4.2 Conjecture Regarding \( r = -1 \) When \( r = -1 \): \[ S_n = a - a + a - a + \ldots \] The terms alternate between \( a \) and \( -a \). The sum depends on whether \( n \) is even or odd: - If \( n \) is even, \( S_n = 0 \). - If \( n \) is odd, \( S_n = a \). **Conjecture**: The sequence is divergent because it does not approach a single value as \( n \rightarrow \infty \). ### 1.6.1 Possible Values of \( r \) such that \( -1 < r < 1 \) Three possible values of \( r \) in the interval \( -1 < r < 1 \) could be: 1. \( r = 0.5 \) 2. \( r = -0.5 \) 3. \( r = 0.9 \) ### 1.6.5 and 1.6.6 Areas of Paper Pieces 1. **Step 4**: The first piece of paper has an area of \( \frac{1}{2} \) the area of A4. The area of A4 is approximately \( 0.297 \, m^2 \) or \( 297 \, cm^2 \). Thus, the area of the first piece is: \[ \text{Area}_1 = \frac{1}{2} \times 297 \, cm^2 = 148.5 \, cm^2 \] 2. **Step 5**: The second piece of paper has an area of \( \frac{1}{4} \) the area of A4: \[ \text{Area}_2 = \frac{1}{4} \times 297 \, cm^2 = 74.25 \, cm^2 \] 3. **Next Three Areas**: Continuing this pattern, the areas of the next three pieces of paper would be: - Third piece: \( \frac{1}{8} \times 297 \, cm^2 = 37.3125 \, cm^2 \) - Fourth piece: \( \frac{1}{16} \times 297 \, cm^2 = 18.65625 \, cm^2 \) - Fifth piece: \( \frac{1}{32} \times 297 \, cm^2 = 9.328125 \, cm^2 \) Thus, the areas of the next three pieces of paper are approximately: 1. \( 37.31 \, cm^2 \) 2. \( 18.66 \, cm^2 \) 3. \( 9.33 \, cm^2 \)

Answered by UpStudy AI and reviewed by a Professional Tutor

error msg
Explain
Simplify this solution

Extra Insights

As \( n \rightarrow \infty \) and \( r < 1 \), \( r^n \) converges to 0, leading to the sum \( S \) for a geometric series defined by \( S = \frac{a}{1 - r} \). However, when \( r = 1 \), the series becomes a simple repetition of \( a \) yielding \( S_n = na \), which diverges as \( n \) grows. For \( r = -1 \), the series oscillates between two values, namely \( S_n = a, 0, a, 0, \ldots \). Hence, the sequence is divergent since it does not approach a single limit as \( n \) increases endlessly. This fun dance between values showcases how different ratios impact the behavior of sequences!

Try Premium now!
Try Premium and ask Thoth AI unlimited math questions now!
Maybe later Go Premium
Study can be a real struggle
Why not UpStudy it?
Select your plan below
Premium

You can enjoy

Start now
  • Step-by-step explanations
  • 24/7 expert live tutors
  • Unlimited number of questions
  • No interruptions
  • Full access to Answer and Solution
  • Full Access to PDF Chat, UpStudy Chat, Browsing Chat
Basic

Totally free but limited

  • Limited Solution
Welcome to UpStudy!
Please sign in to continue the Thoth AI Chat journey
Continue with Email
Or continue with
By clicking “Sign in”, you agree to our Terms of Use & Privacy Policy