3.4. Jemifer wishes to buy a new bike on hire purchase. The price of the bike is R15 000. She pays a deposit of \( 10 \% \) of the price. She will pay the rest off at an interest rate of \( 11 \% \) p.a. over four years. What will her monthly payments be?
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To solve for Jemifer's monthly payments, we first determine the deposit amount. The deposit is \( 10\% \) of R15,000, which is R1,500. This means the remaining amount to finance is R15,000 - R1,500 = R13,500. Next, we need to calculate the total amount she will pay over four years. With an interest rate of \( 11\% \) p.a. compounded monthly, the effective monthly interest rate is \( \frac{11\%}{12} = 0.0091667 \). Using the formula for the monthly payment on an installment loan, which is given by: \[ M = P \frac{r(1+r)^n}{(1+r)^n - 1} \] where: - \( M \) is the total monthly payment, - \( P \) is the principal loan amount (R13,500), - \( r \) is the monthly interest rate (0.0091667), - \( n \) is the number of payments (4 years × 12 months = 48). Substituting the values, we get: \[ M = 13500 \frac{0.0091667(1+0.0091667)^{48}}{(1+0.0091667)^{48} - 1} \] Calculating this gives us: \[ M \approx 13500 \frac{0.0091667(1.491825)}{0.491824} \approx 13500 \frac{0.013672}{0.491824} \approx 13500 \times 0.02782 \approx R375.69 \] Therefore, Jemifer's monthly payments would be approximately R375.69.