3. Find the vertex form for \( f(x)=4 x^{2}+4 x-3 \) and then find the intercepts, the vertex, the maximum or minimum, and the range.
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To convert the quadratic function \( f(x) = 4x^2 + 4x - 3 \) into vertex form, we can complete the square. Start by factoring out the 4 from the first two terms: \( f(x) = 4(x^2 + x) - 3 \). Next, take half of the coefficient of \( x \) (which is \( 1 \)), square it to get \( \frac{1}{4} \), and adjust the equation accordingly: \( f(x) = 4\left(x^2 + x + \frac{1}{4} - \frac{1}{4}\right) - 3 = 4\left((x + \frac{1}{2})^2 - \frac{1}{4}\right) - 3 = 4(x + \frac{1}{2})^2 - 4 - 3 = 4(x + \frac{1}{2})^2 - 7 \). Now, the vertex form is \( f(x) = 4\left(x + \frac{1}{2}\right)^2 - 7 \), where the vertex is at \( V\left(-\frac{1}{2}, -7\right) \). The intercepts can be found by setting \( f(x) = 0 \) to find the x-intercepts, which can be derived from solving the equation or recognizing through the vertex form that the parabola opens upwards. The minimum value occurs at the vertex, meaning the function has a minimum of \(-7\). The range of the function is \( y \geq -7 \) since it opens upward. In summary: - Vertex: \( \left(-\frac{1}{2}, -7\right) \) - Minimum: \(-7\) - Range: \( [-7, \infty) \) Also, keep in mind that the x-intercepts can be calculated using the quadratic formula or factoring, leading to the specific points where \( f(x) \) crosses the x-axis.