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Analyze the polynomial function \( f(x)=x^{2}(x-3) \) using parts (a) through (e). (a) Determine the end behavior of the graph of the function. The graph of \( f \) behaves like \( y=x^{3} \) for large values of \( |x| \). (b) Find the \( x \) - and \( y \)-intercepts of the graph of the function. The \( x \)-intercept(s) is/are (Simplify your answer. Type an integer or a fraction. Use a comma to separate answers as needed. Type each answer only once.)

Ask by Munoz George. in the United States
Feb 24,2025

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Tutor-Verified Answer

Answer

The x-intercepts are x = 0 and x = 3.

Solution

We are given the function f(x) = x²(x – 3), which can also be written as f(x) = x³ – 3x². (a) End Behavior: Since this is a cubic polynomial with a positive leading coefficient, as x → ∞, f(x) behaves like x³ and goes to +∞; and as x → –∞, f(x) behaves like x³ and goes to –∞. (b) Intercepts: • x-intercepts: Set f(x) = 0.   x²(x – 3) = 0   This gives x² = 0 or x – 3 = 0,   so x = 0 or x = 3.   Thus, the x-intercepts are x = 0 and x = 3. • y-intercept: Evaluate f(0).   f(0) = (0)²(0 – 3) = 0.   So, the y-intercept is 0.

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Bonus Knowledge

The \( x \)-intercept occurs when \( f(x) = 0 \). Setting the polynomial equal to zero gives: \[ x^{2}(x - 3) = 0 \] This leads to two equations: \( x^{2} = 0 \) and \( x - 3 = 0 \). Solving \( x^{2} = 0 \) gives \( x = 0 \), and solving \( x - 3 = 0 \) gives \( x = 3 \). Therefore, the \( x \)-intercepts are \( 0, 3 \). To find the \( y \)-intercept, evaluate \( f(0) \): \[ f(0) = 0^{2}(0 - 3) = 0 \] Thus, the \( y \)-intercept is also \( 0 \). The \( x \)-intercepts are \( 0, 3 \) and the \( y \)-intercept is \( 0 \).

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