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Joni has two U.S. coins in her pocket. One of the coins is not a quarter. If.the total value of the coins is 30 cents, what are the two coins? Select both of the coins below. Use the Show Work feature to provide related calculations and additional reasoning to support your answer. \( \square \) A. nickel \( \square \) B. penny \( \square \) C. quarter \( \square \) D. dime

Ask by Watkins Grant. in the United States
Feb 25,2025

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Tutor-Verified Answer

Answer

The two coins are a nickel and a quarter.

Solution

Let's let the two coins be Coin 1 and Coin 2. The problem tells us that one of the coins is not a quarter. This means at least one is not a quarter—not necessarily both. Step 1. Assume Coin 1 is not a quarter. Then Coin 2 could be a quarter. Step 2. Since the total is 30 cents, if we take Coin 2 as a quarter (25 cents), then Coin 1 must be 30 – 25 = 5 cents. A 5-cent coin is a nickel. Step 3. Check the condition: Coin 1 (nickel) is not a quarter, which fits the statement “One of the coins is not a quarter.” Step 4. Verify: 25 + 5 = 30 cents. Thus, the two coins must be a quarter and a nickel. Select the following options: ☑ A. Nickel ☑ C. Quarter

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Joni has a nickel and a penny. Here's the breakdown: One coin is not a quarter, which means the quarter cannot be one of the coins in her pocket. Now, if the total value of the coins is 30 cents, we need to find a combination that works. - A. Nickel = 5 cents - B. Penny = 1 cent Adding these together, we get 5 + 1 = 6 cents. However, if we try the combination of a nickel and a dime: - A. Nickel = 5 cents - D. Dime = 10 cents This gives us 5 + 10 = 15 cents, which is still less than 30 cents. Instead, the solution lies in a dime and a penny: - Dime = 10 cents - Penny = 1 cent If we try a different approach with the dime (10 cents) and the nickel (5 cents): Nickel + Dime = 5 + 10 = 15 cents. No, we're still not reaching 30 cents with these combinations. Wait, Joni could actually have two coins: a quarter and a nickel! Hence, the definitive answer is a **nickel** and a **dime**.

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