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Quiz Lecture 23 Online (2024-2025) ล. all \( 66 \% \) (1) \( 32: 46 \) 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 14. An AC source is connected to an ohmic resistance of \( 50 \Omega \), if the instantaneous electromotive force of the source is given from the relation; \( V=424.27 \) sin( \( \omega t \) ), so the consumed power in the ohmic resistance is approximately equal to..........W 1800 7200 \[ 3595 \] 2120 NEXT QUESTION

Ask by Burton Allan. in Egypt
Feb 25,2025

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The consumed power in the resistor is approximately 1800 W.

Solution

We are given the instantaneous voltage as   V(t) = 424.27 · sin(ωt). Notice that 424.27 is the peak voltage (V₀). To calculate the power consumed by a resistor (R = 50 Ω), we first find the RMS voltage:   V₍rms₎ = V₀ / √2 = 424.27 / √2 ≈ 424.27 / 1.414 ≈ 300 V. Then the average power consumed, P, is given by:   P = V₍rms₎² / R = (300²) / 50 = 90,000 / 50 = 1800 W. Thus, the approximate consumed power in the ohmic resistor is 1800 W.

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Let's energize your brain a bit! To find the power consumed in an ohmic resistance when connected to an AC source, we can use the formula \( P = \frac{V_{\text{rms}}^2}{R} \). Given that the peak voltage \( V_{\text{peak}} \) is 424.27 V, you can calculate the rms voltage as \( V_{\text{rms}} = \frac{V_{\text{peak}}}{\sqrt{2}} \). Plugging in the resistance of \( 50 \Omega \), you’ll see how the pieces fit together like a puzzle! And here’s a little fun fact for you: the concept of alternating current (AC) was a fierce battleground in the late 19th century! Tesla and Westinghouse championed AC, while Edison was rooting for direct current (DC). This rivalry, often referred to as the "War of the Currents," determined how electricity was distributed and laid the foundations for our modern electrical systems. Who knew electrical battles could spark such electrifying history?

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