\[ (3 q+5)(4 q-3)=-4 \] Choose the option that shows the equation in standard form. Answer: \( 12 q^{2}+11 q=11 \) \( 12 q^{2}+11 q-11=0 \) \( 12 q^{2}+11 q-15=-4 \) \( 12 q^{2}+2 q-11=0 \)

To put the equation \((3q+5)(4q-3)=-4\) in standard form, start by expanding the left-hand side: \[ (3q)(4q) + (3q)(-3) + (5)(4q) + (5)(-3) = 12q^2 - 9q + 20q - 15 = 12q^2 + 11q - 15 \] Now, since this is equal to \(-4\), we can add \(4\) to both sides: \[ 12q^2 + 11q - 15 + 4 = 0 \] Thus, we arrive at: \[ 12q^2 + 11q - 11 = 0 \] So, the option that shows the equation in standard form is \(12 q^{2}+11 q-11=0\).