\( 1 \leftarrow \quad \begin{array}{l}\text { Perform the division. } \\ \frac{48 y^{11}-54 y^{7}+6 y^{5}}{6 y^{5}} \\ \frac{48 y^{11}-54 y^{7}+6 y^{5}}{6 y^{5}}=\square \\ \text { (Simplify your answer. Use integers or fractions for ? }\end{array} \)

To perform the division, we divide each term in the numerator by \( 6y^5 \): \[ \frac{48y^{11}}{6y^5} - \frac{54y^7}{6y^5} + \frac{6y^5}{6y^5} \] Calculating each term: 1. \( \frac{48y^{11}}{6y^5} = 8y^6 \) 2. \( \frac{54y^7}{6y^5} = 9y^2 \) 3. \( \frac{6y^5}{6y^5} = 1 \) Now, putting it all together, we simplify: \[ 8y^6 - 9y^2 + 1 \] So the simplified answer is: \[ 8y^6 - 9y^2 + 1 = \square \]