The probability that a student chosen at random from a class has brown hair is \( \frac{7}{13} \). The probability that they have ginger hair is \( \frac{5}{26} \). What is the probability that a student chosen from the class at random has either brown hair or ginger hair? Give your answer as a fraction.

Given: - The probability of a student having brown hair is \( \frac{7}{13} \). - The probability of a student having ginger hair is \( \frac{5}{26} \). We need to find the probability that a student chosen at random from the class has either brown hair or ginger hair. To find the probability of either event happening, we add the probabilities of the individual events. Therefore, the probability of a student having either brown hair or ginger hair is: \[ \frac{7}{13} + \frac{5}{26} \] Let's calculate this. Calculate the value by following steps: - step0: Calculate: \(\frac{7}{13}+\frac{5}{26}\) - step1: Reduce fractions to a common denominator: \(\frac{7\times 2}{13\times 2}+\frac{5}{26}\) - step2: Multiply the numbers: \(\frac{7\times 2}{26}+\frac{5}{26}\) - step3: Transform the expression: \(\frac{7\times 2+5}{26}\) - step4: Multiply the numbers: \(\frac{14+5}{26}\) - step5: Add the numbers: \(\frac{19}{26}\) The probability that a student chosen at random from the class has either brown hair or ginger hair is \( \frac{19}{26} \).