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Find \( \frac{d y}{d x} \) by implicit differentiation. \[ x^{8}+y^{5}=4 \] \( \frac{d y}{d x}=\square \)

Ask by Rowe Tucker. in the United States
Mar 20,2025

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Answer

\[ \frac{dy}{dx} = -\frac{8x^7}{5y^4} \]

Solution

Differentiate both sides of \[ x^8 + y^5 = 4 \] with respect to \( x \). 1. The derivative of \( x^8 \) is \[ 8x^7. \] 2. The derivative of \( y^5 \) with respect to \( x \) requires the chain rule: \[ \frac{d}{dx}(y^5) = 5y^4 \frac{dy}{dx}. \] 3. The derivative of the constant \( 4 \) is \( 0 \). Thus, we have: \[ 8x^7 + 5y^4 \frac{dy}{dx} = 0. \] Solve for \( \frac{dy}{dx} \): Subtract \( 8x^7 \) from both sides: \[ 5y^4 \frac{dy}{dx} = -8x^7. \] Divide both sides by \( 5y^4 \): \[ \frac{dy}{dx} = -\frac{8x^7}{5y^4}. \] The final answer is: \[ \frac{dy}{dx} = -\frac{8x^7}{5y^4}. \]

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To find \( \frac{d y}{d x} \) using implicit differentiation, we start with the equation: \[ x^{8} + y^{5} = 4. \] Differentiate both sides with respect to \( x \): \[ \frac{d}{dx}(x^8) + \frac{d}{dx}(y^5) = \frac{d}{dx}(4). \] This gives us: \[ 8x^{7} + 5y^{4} \frac{dy}{dx} = 0. \] Now, solve for \( \frac{dy}{dx} \): \[ 5y^{4} \frac{dy}{dx} = -8x^{7}, \] \[ \frac{dy}{dx} = -\frac{8x^{7}}{5y^{4}}. \] Thus, the derivative \( \frac{d y}{d x} \) is: \[ \frac{d y}{d x} = -\frac{8x^{7}}{5y^{4}}. \]

Related Questions

Find the critical points of the following function. Use the Second Derivative Test to determine (if possible) whether each critical point corresponds to a local maximum, local minimum, or saddle point. If the Second Derivative Test is inconclusive, determine the behavior of the function at the critical points. \[ f(x, y)=-8 x^{2}+5 y^{2}-13 \] Determine the behavior of the function at any of the critical points for which the Second Derivative Test is inconclusive. Select the correct choice below and, if necessary, fill in the answer box(es) within your choice. A. Among these points, there are local minimum/minima at \( \square \) , and no local maxima or saddle points. (Type an ordered pair. Use a comma to separate answers as needed.) B. Among these points, there are saddle point(s) at \( \square \) , and no local maxima or minima. (Type an ordered pair. Use a comma to separate answers as needed.) C. Among these points, there are local maximum/maxima at \( \square \) , local minimum/minima at points. \( \square \) , and no saddle (Type an ordered pair. Use a comma to separate answers as needed.) D. Among these points, there are local maximum/maxima at \( \square \) , saddle point(s) at (Type an ordered pair. Use a comma to separate answers as needed.) \( \square \) , and no local minima. E. Among these points, there are local maximum/maxima at at \( \square \) \( \square \) , local minimum/minima at . \( \square \) , and saddle point(s) (Type an ordered pair. Use a comma to separate answers as needed.)

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