Given the function $$ f(x)=3 x^{2}-2 x+3 $$. Calculate the following values: $$ f(-2)=\square $$ $$ f(-1)=\square $$ $$ f(0)=\square $$ $$ f(1)=\square $$ $$ f(2)=\square $$ Question Help: $$ \square $$ Video

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**Step 1. Evaluate $$ f(-2) $$**  
Substitute $$ x = -2 $$ into the function:  
$$
f(-2) = 3(-2)^2 - 2(-2) + 3.
$$  
Calculate step by step:  
$$
(-2)^2 = 4 \quad \Rightarrow \quad 3 \times 4 = 12,
$$  
$$
-2(-2) = 4,
$$  
Now, sum together:  
$$
f(-2) = 12 + 4 + 3 = 19.
$$

**Step 2. Evaluate $$ f(-1) $$**  
Substitute $$ x = -1 $$:  
$$
f(-1) = 3(-1)^2 - 2(-1) + 3.
$$  
Calculate:  
$$
(-1)^2 = 1 \quad \Rightarrow \quad 3 \times 1 = 3,
$$  
$$
-2(-1) = 2,
$$  
Sum together:  
$$
f(-1) = 3 + 2 + 3 = 8.
$$

**Step 3. Evaluate $$ f(0) $$**  
Substitute $$ x = 0 $$:  
$$
f(0) = 3(0)^2 - 2(0) + 3.
$$  
Calculate:  
$$
3(0)^2 = 0, \quad -2(0) = 0,
$$  
Thus,  
$$
f(0) = 0 + 0 + 3 = 3.
$$

**Step 4. Evaluate $$ f(1) $$**  
Substitute $$ x = 1 $$:  
$$
f(1) = 3(1)^2 - 2(1) + 3.
$$  
Calculate:  
$$
(1)^2 = 1 \quad \Rightarrow \quad 3 \times 1 = 3,
$$  
$$
-2(1) = -2,
$$  
So,  
$$
f(1) = 3 - 2 + 3 = 4.
$$

**Step 5. Evaluate $$ f(2) $$**  
Substitute $$ x = 2 $$:  
$$
f(2) = 3(2)^2 - 2(2) + 3.
$$  
Calculate:  
$$
(2)^2 = 4 \quad \Rightarrow \quad 3 \times 4 = 12,
$$  
$$
-2(2) = -4,
$$  
Thus,  
$$
f(2) = 12 - 4 + 3 = 11.
$$

**Final Answers:**  
$$ f(-2)=19 $$  
$$ f(-1)=8 $$  
$$ f(0)=3 $$  
$$ f(1)=4 $$  
$$ f(2)=11 $$
$$ f(-2)=19 $$, $$ f(-1)=8 $$, $$ f(0)=3 $$, $$ f(1)=4 $$, $$ f(2)=11 $$.

Given the function \( f(x)=3 x^{2}-2 x+3 \). Calculate the following values: \( f(-2)=\square \) \( f(-1)=\square \) \( f(0)=\square \) \( f(1)=\square \) \( f(2)=\square \) Question Help: \( \square \) Video

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