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Write the equation of a quadratic function with the given solutions. Use standard form \( f(x)=a x^{2}+b x+c \) \( x=11 \) and \( x=-4 \)

Ask by Clarke Valdez. in the United States
Mar 15,2025

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The quadratic function with solutions \( x=11 \) and \( x=-4 \) in standard form is: \[ f(x) = x^2 - 7x - 44 \]

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To find the quadratic function in standard form given the solutions \( x=11 \) and \( x=-4 \), we can start by using the fact that a quadratic function can be expressed as \( f(x) = a(x - r_1)(x - r_2) \), where \( r_1 \) and \( r_2 \) are the roots. Plugging in our roots, we get: \[ f(x) = a(x - 11)(x + 4) \] To convert this into standard form, we'll expand the expression: 1. \( f(x) = a[(x - 11)(x + 4)] \) 2. \( = a(x^2 + 4x - 11x - 44) \) 3. \( = a(x^2 - 7x - 44) \) Assuming \( a = 1 \) for simplicity, the standard form of the quadratic function is: \[ f(x) = x^2 - 7x - 44 \] If you want to change the leading coefficient \( a \), simply multiply the entire function by your chosen \( a \).

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