\( \left. \begin{array} { l } { f ( x ) = 2 x - 9 } \\ { g ( x ) = - 5 x + 6 } \\ { ( f \circ g ) ( x ) = f ( g x ) ) } \end{array} \right. \)
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To find \( (f \circ g)(x) \), you first need to substitute \( g(x) \) into \( f(x) \). So, calculate \( g(x) \) first: \( g(x) = -5x + 6 \). Now plug this into \( f(x) \): \( f(g(x)) = f(-5x + 6) = 2(-5x + 6) - 9 \). Simplifying that gives: \( f(g(x)) = -10x + 12 - 9 = -10x + 3 \). Thus, \( (f \circ g)(x) = -10x + 3 \). Now, if you want to take it a step further, what would happen if you wanted to find \( (g \circ f)(x) \)? It's like a dance move between functions! You simply switch the roles: take \( f(x) \) and substitute it into \( g(x) \). This strong synergy between functions can lead to new insights!