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According to the U.S. Census Bureau, the probability that a randomly selected worker primarily drives a car to work is 0.7637 . The probability that a randomly selected worker primarily takes public transportation to work is 0.0509 . Complete parts (a) through (d). (a) What is the probability that a randomly selected worker primarily drives a car or takes publio transportation to work? P(worker drives a car or takes public transportation to work) \( =0.8146 \) (Round to four decimal places as needed.) (b) What is the probability that a randomly selected worker primarily neither drives a car nor takes public transportation to work? P(worker neither drives a car nor takes public transportation to work) \( =0.1854 \) (Round to four decimal places as needed.) (c) What is the probability that a randomly selected worker primarily does not drive a car to work? P(worker does not drive a car to work) \( =\square \) (Round to four decimal places as needed.)

Ask by Stuart Wood. in the United States
Mar 19,2025

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(a) The probability that a worker primarily drives a car or takes public transportation is 0.8146. (b) The probability that a worker neither drives a car nor takes public transportation is 0.1854. (c) The probability that a worker does not drive a car is 0.2363.

Solution

(a) We have \[ P(\text{car or public transportation}) = P(\text{car}) + P(\text{public transportation}) \] Substituting the given values: \[ P(\text{car or public transportation}) = 0.7637 + 0.0509 = 0.8146 \] (b) The probability that a worker neither drives a car nor takes public transportation is the complement of the result in part (a): \[ P(\text{neither car nor public transportation}) = 1 - 0.8146 = 0.1854 \] (c) The probability that a worker does not drive a car is: \[ P(\text{not drive car}) = 1 - P(\text{drive car}) = 1 - 0.7637 = 0.2363 \]

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The Deep Dive

The probability that a randomly selected worker does not drive a car to work can be found by subtracting the probability that they do drive a car from 1. Since the probability of driving a car is 0.7637, we have: P(worker does not drive a car to work) = 1 - P(worker drives a car to work) = 1 - 0.7637 = 0.2363. So, P(worker does not drive a car to work) = 0.2363 (rounded to four decimal places). Now, let's sum it up with some fun trivia: did you know that public transportation systems reduce overall traffic congestion? With more people opting for buses and trains, we can enjoy clearer roads and cleaner air! And here's another interesting fact: the act of driving a car to work can actually help you feel more in control, but it also means you might miss out on the chance to read a book or catch up on work while on the go via public transit!

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