According to the U.S. Census Bureau, the probability that a randomly selected worker primarily drives a car to work is 0.7637 . The probability that a randomly selected worker primarily takes public transportation to work is 0.0509 . Complete parts (a) through (d). (a) What is the probability that a randomly selected worker primarily drives a car or takes publio transportation to work? P(worker drives a car or takes public transportation to work) $$ =0.8146 $$ (Round to four decimal places as needed.) (b) What is the probability that a randomly selected worker primarily neither drives a car nor takes public transportation to work? P(worker neither drives a car nor takes public transportation to work) $$ =0.1854 $$ (Round to four decimal places as needed.) (c) What is the probability that a randomly selected worker primarily does not drive a car to work? P(worker does not drive a car to work) $$ =\square $$ (Round to four decimal places as needed.)

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UpStudy AI · Accepted Answer

(a) We have  
$$
P(\text{car or public transportation}) = P(\text{car}) + P(\text{public transportation})
$$
Substituting the given values:
$$
P(\text{car or public transportation}) = 0.7637 + 0.0509 = 0.8146
$$

(b) The probability that a worker neither drives a car nor takes public transportation is the complement of the result in part (a):
$$
P(\text{neither car nor public transportation}) = 1 - 0.8146 = 0.1854
$$

(c) The probability that a worker does not drive a car is:
$$
P(\text{not drive car}) = 1 - P(\text{drive car}) = 1 - 0.7637 = 0.2363
$$
(a) The probability that a worker primarily drives a car or takes public transportation is 0.8146. (b) The probability that a worker neither drives a car nor takes public transportation is 0.1854. (c) The probability that a worker does not drive a car is 0.2363.

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