Q7. How many milliliters of a 1.50 M acetic acid solution will be needed to create 2.50 L of a 0.250M solution? (2 marks)

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To solve this problem, we can use the dilution formula, which is given by:

$$
C_1 V_1 = C_2 V_2
$$

where:
- $$ C_1 $$ is the concentration of the stock solution (1.50 M),
- $$ V_1 $$ is the volume of the stock solution we need to find,
- $$ C_2 $$ is the concentration of the diluted solution (0.250 M),
- $$ V_2 $$ is the volume of the diluted solution (2.50 L).

We need to rearrange the formula to solve for $$ V_1 $$:

$$
V_1 = \frac{C_2 V_2}{C_1}
$$

Now, let's substitute the known values into the equation:

- $$ C_1 = 1.50 \, \text{M} $$
- $$ C_2 = 0.250 \, \text{M} $$
- $$ V_2 = 2.50 \, \text{L} $$

Now we can calculate $$ V_1 $$:
Calculate the value by following steps:
- step0: Calculate:
  $$\frac{\left(0.25\times 2.5\right)}{1.5}$$
- step1: Remove the parentheses:
  $$\frac{0.25\times 2.5}{1.5}$$
- step2: Multiply the numbers:
  $$\frac{0.625}{1.5}$$
- step3: Convert the expressions:
  $$\frac{\frac{5}{8}}{\frac{3}{2}}$$
- step4: Multiply by the reciprocal:
  $$\frac{5}{8}\times \frac{2}{3}$$
- step5: Reduce the numbers:
  $$\frac{5}{4}\times \frac{1}{3}$$
- step6: Multiply the fractions:
  $$\frac{5}{4\times 3}$$
- step7: Multiply:
  $$\frac{5}{12}$$
The calculation gives us:

$$
V_1 = \frac{0.250 \times 2.50}{1.50} = \frac{5}{12} \text{ L} \approx 0.4167 \text{ L}
$$

To convert this volume into milliliters, we multiply by 1000:

$$
V_1 \approx 0.4167 \times 1000 \text{ mL} \approx 416.67 \text{ mL}
$$

Thus, approximately **416.67 mL** of the 1.50 M acetic acid solution is needed to create 2.50 L of a 0.250 M solution.
Approximately 416.67 mL of the 1.50 M acetic acid solution is needed.

Q7. How many milliliters of a 1.50 M acetic acid solution will be needed to create 2.50 L of a 0.250M solution? (2 marks)

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