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\( \therefore \sin \theta = 3 \cos \theta \)

Ask by Lambert Hills. in South Africa
Mar 08,2025

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Answer

\[ \theta = \arctan(3) + k\pi, \quad k \in \mathbb{Z} \]

Solution

1. Start with the equation: \[ \sin \theta = 3 \cos \theta. \] 2. Divide both sides by \(\cos \theta\) (assuming \(\cos \theta \neq 0\)): \[ \frac{\sin \theta}{\cos \theta} = \frac{3 \cos \theta}{\cos \theta}. \] This simplifies to: \[ \tan \theta = 3. \] 3. The general solution for \(\tan \theta = 3\) is: \[ \theta = \arctan(3) + k\pi, \quad k \in \mathbb{Z}. \]

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Beyond the Answer

Did you know that the equation \( \sin \theta = 3 \cos \theta \) can be transformed into a more recognizable form using the tangent function? You can rewrite it as \( \tan \theta = \frac{1}{3} \). Understanding the relationship between sine, cosine, and tangent is key in trigonometry and can help you solve a range of problems! Now, how do we find the angles that satisfy this equation? By recognizing \( \tan \theta = \frac{1}{3} \), you can use the inverse tangent function: \( \theta = \tan^{-1}\left(\frac{1}{3}\right) \). This gives you an angle in the first quadrant, but remember that the tangent function is periodic, so there will be additional solutions in other quadrants as well!

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