Find the \( x \)-intercept and \( y \)-intercept of the line. \[ \begin{array}{l}2 x+4 y=-12 \\ y \text {-intercept: } \\ y \text {-intercept: } \square\end{array} \]

To find the intercepts of the line given by the equation \( 2x + 4y = -12 \), we can follow a couple of straightforward steps! For the \( y \)-intercept, set \( x = 0 \): \[ 2(0) + 4y = -12 \implies 4y = -12 \implies y = -3. \] So, the \( y \)-intercept is \( (0, -3) \). For the \( x \)-intercept, set \( y = 0 \): \[ 2x + 4(0) = -12 \implies 2x = -12 \implies x = -6. \] Therefore, the \( x \)-intercept is \( (-6, 0) \). Putting it all together: - \( y \)-intercept: \( (0, -3) \) - \( x \)-intercept: \( (-6, 0) \)