Question
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\( 8=12+\sqrt{2-2 x} \) The siluton set is \( \square \).

Ask by Gough Fuentes. in the United States
Feb 25,2025

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Tutor-Verified Answer

Answer

The solution set is empty, \(\square\).

Solution

Solve the equation \( 8=12+\sqrt{2-2x} \). Solve the equation by following steps: - step0: Solve for \(x\): \(8=12+\sqrt{2-2x}\) - step1: Swap the sides: \(12+\sqrt{2-2x}=8\) - step2: Move the constant to the right side: \(\sqrt{2-2x}=8-12\) - step3: Subtract the numbers: \(\sqrt{2-2x}=-4\) - step4: The statement is false for any value of \(x:\) \(x \notin \mathbb{R}\) The equation \(8=12+\sqrt{2-2x}\) does not have any real solutions. Therefore, the solution set is empty, denoted as \(\square\).

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The Deep Dive

To solve the equation \( 8=12+\sqrt{2-2 x} \), start by isolating the square root. Subtract 12 from both sides to get \( -4=\sqrt{2-2 x} \). Since the square root cannot equal a negative number, there are no real solutions, meaning the solution set is empty: \( \emptyset \). Now, let's talk about the reality of square roots! Did you know that square roots reveal the beauty of numbers, like how the square root of 9 is 3 because 3 times 3 equals 9? But be wary; that root can’t take on negative values—it's all about the positivity! Have you heard of complex numbers? They extend the number system by introducing imaginary units like \( i \), where \( i^2 = -1 \). If you ever encounter situations with negative roots, those complex numbers can save the day and allow for all sorts of exciting mathematical explorations!

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