Consider the equation \( 7 x+9 y=-18 \) A line parallel to the above line would have a slope of A line perpendicular to the above line would have a slope of Submit Question

To find the slope of the line given by the equation \( 7x + 9y = -18 \), we can rearrange it into the slope-intercept form \( y = mx + b \). Doing so, we isolate \( y \): \[ 9y = -7x - 18 \implies y = -\frac{7}{9}x - 2. \] Thus, the slope (\( m \)) of the original line is \( -\frac{7}{9} \). A line parallel to this would have the same slope, which is also \( -\frac{7}{9} \). In contrast, the slope of a line perpendicular to this one is the negative reciprocal of the slope of the original line. Therefore, the slope for the perpendicular line would be \[ \frac{9}{7}. \]