Express the given function $$ h $$ as a composition of two functions $$ f $$ and $$ g $$ so that $$ h(x)=(f \circ g)(x) $$, where one of the functions is $$ 6 x-2 $$. $$ h(x)=(6 x-2)^{7} $$ $$ f(x)=\square $$

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1. We are given the function  
   $$
   h(x)=(6x-2)^7.
   $$

2. We need to express $$ h(x) $$ as a composition $$(f \circ g)(x)$$, where one of the functions is $$6x-2$$.

3. Let
   $$
   g(x)=6x-2.
   $$

4. Since $$ h(x)=(6x-2)^7 $$, we can write it as
   $$
   h(x)=g(x)^7.
   $$

5. Therefore, we choose
   $$
   f(x)=x^7.
   $$

6. With these choices, the composition is
   $$
   (f \circ g)(x)=f(g(x))=(6x-2)^7,
   $$
   which matches the given function $$ h(x) $$.

Thus, the function $$ f(x) $$ is  
$$
f(x)=x^7.
$$
$$ f(x) = x^7 $$

Express the given function \( h \) as a composition of two functions \( f \) and \( g \) so that \( h(x)=(f \circ g)(x) \), where one of the functions is \( 6 x-2 \). \( h(x)=(6 x-2)^{7} \) \( f(x)=\square \)

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