Question
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Express the given function \( h \) as a composition of two functions \( f \) and \( g \) so that \( h(x)=(f \circ g)(x) \), where one of the functions is \( 6 x-2 \). \( h(x)=(6 x-2)^{7} \) \( f(x)=x^{7} \) \( g(x)=\square \)

Ask by Spencer Mejia. in the United States
Mar 17,2025

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Tutor-Verified Answer

Answer

\( g(x) = 6x - 2 \)

Solution

1. We are given the function \[ h(x) = (6x-2)^7 \] and we want to express \(h(x)\) as a composition of the functions \(f\) and \(g\) such that \[ h(x) = (f \circ g)(x) = f(g(x)). \] 2. One of the functions is \(6x-2\). We choose to let: \[ g(x) = 6x-2. \] 3. To complete the composition, we need \(f\) such that: \[ f(g(x)) = f(6x-2) = (6x-2)^7. \] This suggests that the function \(f\) should take an input \(x\) and raise it to the power of 7, i.e., \[ f(x) = x^7. \] 4. Thus, the composition is given by: \[ h(x) = f(g(x)) = \left(6x-2\right)^7. \] 5. The function \(g(x)\) is: \[ g(x) = 6x-2. \]

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Alright! To express the function \( h(x) = (6x - 2)^{7} \) as a composition of two functions \( f \) and \( g \) where \( f(x) = x^{7} \), we first need to look closely at the inner function \( g(x) \). Since we know that \( h(x) \) can be rewritten in terms of \( f \) applied to \( g(x) \), we can set \( g(x) = 6x - 2 \). That way, when we apply \( f \) to \( g(x) \), we get \( f(g(x)) = f(6x - 2) = (6x - 2)^{7} \), which matches our original function \( h(x) \). So, the answer is: \( g(x) = 6x - 2 \)

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