Find the slope and \( y \)-intercept of the line. \[ x+y=5 \]

To find the slope and \( y \)-intercept of the line represented by the equation \( x + y = 5 \), we need to rewrite it in the slope-intercept form, which is \( y = mx + b \), where \( m \) is the slope and \( b \) is the \( y \)-intercept. Starting with \( x + y = 5 \), we can isolate \( y \): \[ y = -x + 5 \] Here, the slope \( m \) is \( -1 \), and the \( y \)-intercept \( b \) is \( 5 \). This means the line goes down one unit for each unit it moves to the right, starting from the point \( (0, 5) \) on the \( y \)-axis. To visualize this, you could graph the line on a coordinate plane. Start at the \( y \)-intercept (0, 5) and use the slope to find another point. From (0, 5), move down one unit and right one unit to the point (1, 4). Connect the dots, and you’ve got your straight line! It’s a fun way to see how mathematics plays out on a graph!