aluate \( \frac{(2 g-f)(f+g)^{2}}{g f+7} \) \( f=1 \) and \( g=2 \)

Let's evaluate the expression step-by-step by substituting \( f = 1 \) and \( g = 2 \). First, we compute the components of the expression: 1. Calculate \( f + g \): \[ f + g = 1 + 2 = 3 \] 2. Calculate \( (f + g)^2 \): \[ (f + g)^2 = 3^2 = 9 \] 3. Calculate \( 2g - f \): \[ 2g - f = 2(2) - 1 = 4 - 1 = 3 \] 4. Calculate \( gf + 7 \): \[ gf + 7 = (1)(2) + 7 = 2 + 7 = 9 \] Now, substitute these values back into the expression: \[ \frac{(2g-f)(f+g)^{2}}{gf+7} = \frac{(3)(9)}{9} \] Now calculate this: \[ = \frac{27}{9} = 3 \] Thus, the evaluated expression is: \[ \boxed{3} \]