Question
\( 1 \leftarrow \quad \) Factor by grouping. \[ x^{3}-2 x^{2}+3 x-6 \] Select the correct choice below and fill in any answer boxes within your choice. A. \( x^{3}-2 x^{2}+3 x-6=\square \) B. The polynomial is prime.
Ask by Salinas Owen. in the United States
Mar 19,2025
Upstudy AI Solution
Tutor-Verified Answer
Answer
\( x^{3}-2 x^{2}+3 x-6=(x-2)(x^2+3) \)
Solution

Sign in to Unlock Answers for Free!
A Learning Platform Trusted by Millions of Real Students and Teachers.

Answered by UpStudy AI and reviewed by a Professional Tutor
Like
Bonus Knowledge
To factor by grouping, we can rearrange the polynomial as follows: \[ x^{3} - 2x^{2} + 3x - 6 = (x^{3} - 2x^{2}) + (3x - 6) \] Next, we factor out the common factors from each group: \[ x^{2}(x - 2) + 3(x - 2) \] Now, we can factor out the common binomial factor \((x - 2)\): \[ (x - 2)(x^{2} + 3) \] So, the complete factorization is: A. \( x^{3}-2 x^{2}+3 x-6=(x - 2)(x^{2} + 3) \)