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б) \( -15+(-28) ; \) 2. Найдите расстояние между точками координатной прямой: а) \( P(-6) \) и \( Q(-15) \); б) \( S(-5,7) \) и \( T(0,9) \). 3. Ретите уравнение: а) \( 4,6-x=-2,5 \); б) \( y+6 \frac{9}{16}=-3 \frac{7}{24} \). 4. Цева товара повысилясь с 7800 до 9750 р. На сколько процент повысилась цена товара? 5*. Решите уравнение \( |b+5|=11 \).

Ask by Reid Logan. in Russia
Mar 17,2025

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1. \( -15 + (-28) = -43 \) 2. Distance between \( P(-6) \) and \( Q(-15) \) is 9 units; distance between \( S(-5.7) \) and \( T(0.9) \) is 6.6 units. 3. \( x = 7.1 \); \( y = -\frac{473}{48} \) 4. The price increased by 25%. 5. The solutions for \( |b + 5| = 11 \) are \( b = -16 \) and \( b = 6 \).

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Чтобы сложить два отрицательных числа, просто сложите их по модулю и добавьте знак минус. Например, \( -15 + (-28) = -(15 + 28) = -43 \). Чтобы найти расстояние между двумя точками на координатной прямой, используйте формулу: расстояние = |x1 - x2|. В случае P(-6) и Q(-15) это будет |(-6) - (-15)| = |-6 + 15| = |9| = 9. А для точек S(-5.7) и T(0.9) расстояние составит |(-5.7) - (0.9)| = |-6.6| = 6.6.

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