If \( f(x)=\frac{1}{x+1} \), then \( f(1)= \) (c) \( -\frac{1}{4} \) \( \begin{array}{llll}\text { (a) } \frac{1}{4} & \text { (c) } 1\end{array} \)

To find \( f(1) \) for the function \( f(x) = \frac{1}{x + 1} \), we simply substitute \( x \) with \( 1 \): \[ f(1) = \frac{1}{1 + 1} = \frac{1}{2}. \] So, the correct answer is not listed among your options, as none of the options provided match this result! For a fun twist on evaluating functions, it’s quite exciting to see how our answers can change just by tweaking the input values. Also, functions like this one are used in various fields, such as engineering and physics, where they often model behavior that diminishes or approaches a limit, like the way light dissipates over distance or how gravity weakens with altitude!