Andrew and Curt each play in bands. Andrew plays in a band with 28 people in h. There are tirnes as many people in Andrew's band than in Curt's band. How many people are in Curt: band? A. 4 B. 21 C. 35

Let's break down the problem step by step. 1. **Identify the known conditions:** - Andrew's band has 28 people. - There are \( t \) times as many people in Andrew's band than in Curt's band. 2. **Set up the relationship:** - Let \( c \) be the number of people in Curt's band. - According to the problem, we can express the relationship as: \[ 28 = t \cdot c \] 3. **Determine the value of \( t \):** - The problem states that there are \( t \) times as many people in Andrew's band than in Curt's band. This means: \[ t = \frac{28}{c} \] 4. **Evaluate the options:** - We need to check each option to see if it satisfies the equation \( 28 = t \cdot c \). - **Option A: \( c = 4 \)** \[ t = \frac{28}{4} = 7 \] This means Andrew's band has 7 times as many people as Curt's band, which is valid. - **Option B: \( c = 21 \)** \[ t = \frac{28}{21} \approx 1.33 \] This means Andrew's band has approximately 1.33 times as many people as Curt's band, which is valid. - **Option C: \( c = 35 \)** \[ t = \frac{28}{35} \approx 0.8 \] This means Andrew's band has approximately 0.8 times as many people as Curt's band, which is not valid. 5. **Conclusion:** - The valid options are A (4) and B (21). However, since the problem states that there are \( t \) times as many people in Andrew's band than in Curt's band, the only option that fits the context of the problem is: **Curt's band has 4 people.** So the answer is **A. 4**.