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Calculate the value of the symbol in brackets: 31. \( T=a r^{-1}(n) \) if \( T=204, a=8 \) and \( r=0,6 \)

Ask by Vargas Johnston. in South Africa
Jan 31,2025

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Tutor-Verified Answer

Answer

The value of \( n \) is approximately **6.35**.

Solution

To solve for \( n \) in the equation: \[ T = a \cdot r^{-n} \] given: - \( T = 204 \) - \( a = 8 \) - \( r = 0.6 \) **Step 1: Plug in the known values** \[ 204 = 8 \cdot (0.6)^{-n} \] **Step 2: Isolate the exponential term** \[ \frac{204}{8} = (0.6)^{-n} \] \[ 25.5 = (0.6)^{-n} \] **Step 3: Take the natural logarithm of both sides** \[ \ln(25.5) = \ln\left((0.6)^{-n}\right) \] \[ \ln(25.5) = -n \cdot \ln(0.6) \] **Step 4: Solve for \( n \)** \[ n = -\frac{\ln(25.5)}{\ln(0.6)} \] **Step 5: Calculate the values** \[ \ln(25.5) \approx 3.238 \] \[ \ln(0.6) \approx -0.511 \] \[ n = -\frac{3.238}{-0.511} \approx 6.35 \] **Final Answer:** The value of \( n \) is approximately **6.35**.

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To calculate the value of \( n \) in the equation \( T = a r^{-1}(n) \), let's first rearrange the equation to find \( n \). We know: - \( T = 204 \) - \( a = 8 \) - \( r = 0.6 \) Plugging in the values, we have: \[ 204 = 8 \cdot 0.6^{-1}(n) \] Now, calculate \( 0.6^{-1} \): \[ 0.6^{-1} = \frac{1}{0.6} \approx 1.6667 \] So, we can rewrite the equation: \[ 204 = 8 \cdot 1.6667(n) \] Dividing both sides by 8 gives: \[ \frac{204}{8} = 1.6667(n) \] \[ 25.5 = 1.6667(n) \] Now, we divide both sides by \( 1.6667 \): \[ n = \frac{25.5}{1.6667} \approx 15.3 \] Thus, the value of the symbol in brackets, \( n \), is approximately **15.3**.

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