b) \( x^{2}-15 x+56= \)

To solve the quadratic equation \( x^{2}-15x+56=0 \), you can factor it into \( (x-7)(x-8)=0 \). This means \( x = 7 \) and \( x = 8 \) are the solutions. These values can be verified by substituting them back into the original equation. Factoring quadratics can sometimes feel like a treasure hunt! If you’re stuck with the numbers, remember that you can also use the quadratic formula \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \), where \( a = 1, b = -15, c = 56 \). After calculating, you'll arrive at the same solutions: 7 and 8.