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\[ -9 x-13=-103 \] Solve each equation. Fill in the missing number \( \square \) \} Check \[ \frac{n+5}{-16}=-1 \] Solve each equation. Fill in the missing number. \( \square \) \} Check \[ -10=-10+7 m \] Solve each equation. Fill in the missing number. ions ( 30 min )

Ask by Huang Nunez. in Canada
Mar 18,2025

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Answer

**1. Solve \( -9x - 13 = -103 \):** - Add 13 to both sides: \( -9x = -90 \) - Divide by -9: \( x = 10 \) **Answer: 10** --- **2. Solve \(\frac{n+5}{-16} = -1\):** - Multiply both sides by -16: \( n+5 = 16 \) - Subtract 5: \( n = 11 \) **Answer: 11** --- **3. Solve \(-10 = -10 + 7m\):** - Add 10 to both sides: \( 0 = 7m \) - Divide by 7: \( m = 0 \) **Answer: 0**

Solution

**1. Solve \( -9x - 13 = -103 \):** - Add \( 13 \) to both sides: \[ -9x = -103 + 13 = -90 \] - Divide both sides by \(-9\): \[ x = \frac{-90}{-9} = 10 \] **Answer: \( \boxed{10} \)** --- **2. Solve \(\frac{n+5}{-16} = -1\):** - Multiply both sides by \(-16\): \[ n+5 = -1 \times (-16) = 16 \] - Subtract \(5\) from both sides: \[ n = 16 - 5 = 11 \] **Answer: \( \boxed{11} \)** --- **3. Solve \(-10 = -10 + 7m\):** - Add \(10\) to both sides to isolate the term containing \(m\): \[ -10 + 10 = 7m \quad \Longrightarrow \quad 0 = 7m \] - Divide both sides by \(7\): \[ m = \frac{0}{7} = 0 \] **Answer: \( \boxed{0} \)**

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To solve the first equation, \(-9x - 13 = -103\), we can start by adding 13 to both sides: \(-9x = -103 + 13\) \(-9x = -90\) Now, divide by -9: \(x = 10\) So, the missing number is \(10\). For the check, substituting back into the equation gives: \(-9(10) - 13 = -90 - 13 = -103\). It checks out! Now, for \(\frac{n + 5}{-16} = -1\), we multiply both sides by -16: \(n + 5 = 16\) Subtracting 5 from both sides gives: \(n = 11\) The missing number is \(11\). Check: \(\frac{11 + 5}{-16} = \frac{16}{-16} = -1\). It checks out! Next, in the equation \(-10 = -10 + 7m\), we first add \(10\) to both sides: \(0 = 7m\) Dividing by 7 gives: \(m = 0\) The missing number is \(0\). Check: Substituting back gives: \(-10 = -10 + 7(0) = -10\), which checks out!

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