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A 12.0 kg shot put is thrown with 36 N of force. What is its acceleration (with units)

Ask by Chandler Salinas. in the United States
Feb 19,2025

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Answer

The acceleration of the shot put is 3 m/s².

Solution

To find the acceleration of the shot put, we can use the formula for force and mass: \[ F = m \times a \] Given: - Mass of the shot put, \( m = 12.0 \, \text{kg} \) - Force applied, \( F = 36 \, \text{N} \) We can rearrange the formula to solve for acceleration (\( a \)): \[ a = \frac{F}{m} \] Substitute the given values into the formula to find the acceleration of the shot put. Calculate the value by following steps: - step0: Calculate: \(\frac{36}{12}\) - step1: Reduce the numbers: \(\frac{3}{1}\) - step2: Calculate: \(3\) The acceleration of the shot put is 3 m/s².

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Mind Expander

To find the acceleration, you can use Newton's second law of motion, which states that Force (F) equals mass (m) times acceleration (a), represented by the formula F = m * a. Rearranging the equation gives you a = F / m. So, substituting the values: a = 36 N / 12.0 kg = 3.0 m/s². The acceleration of the shot put is 3.0 m/s²! Now, how cool is that? Throwing a heavy shot put with such force generates some serious acceleration, propelling athletes into the air (and sometimes, into the record books!). It's a great example of applying physics in athletics! Additionally, in the world of sports, understanding this physics can help athletes optimize their throws to achieve maximum distance and performance. The quicker they can accelerate the shot put, the farther it travels, making a huge difference during competitions!

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