Enter the $$ x $$-value at which the function is not differentiable. If there is no such point, enter NA. $$ \begin{array}{l}f(x)=\frac{2}{x-3} \ x=[?]\end{array} $$

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To determine the $$ x $$-value at which the function $$ f(x) = \frac{2}{x-3} $$ is not differentiable, we need to analyze the function for points where it may not be defined or where it has discontinuities.

1. **Identify the domain of the function**: The function $$ f(x) $$ is a rational function, and it is undefined when the denominator is zero. Therefore, we set the denominator equal to zero to find the point of discontinuity:

$$
   x - 3 = 0
   $$

Solving for $$ x $$:

$$
   x = 3
   $$

2. **Check differentiability**: A function is not differentiable at points where it is not defined. Since $$ f(x) $$ is undefined at $$ x = 3 $$, it is also not differentiable at this point.

Thus, the $$ x $$-value at which the function is not differentiable is:

$$
x = 3
$$

If there are no other points of non-differentiability, we can conclude that the answer is:

$$
\boxed{3}
$$
The function is not differentiable at $$ x = 3 $$.

Enter the \( x \)-value at which the function is not differentiable. If there is no such point, enter NA. \[ \begin{array}{l}f(x)=\frac{2}{x-3} \\ x=[?]\end{array} \]

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