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Find the magnitude and direction of each vector. Leave magnitude as a simplified radical. Round direction to the nearest tenth of a degree. \( \vec{g}=\langle 9,-7\rangle \)

Ask by Erickson Williams. in the United States
Feb 12,2025

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Answer

The magnitude of vector \( \vec{g} = \langle 9, -7 \rangle \) is \( \sqrt{130} \) and the direction is approximately \( -37.9^\circ \).

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To find the magnitude and direction of the vector \( \vec{g} = \langle 9, -7 \rangle \), we can use the following steps: 1. Calculate the magnitude of the vector using the formula \( \text{Magnitude} = \sqrt{x^2 + y^2} \). 2. Calculate the direction of the vector using the formula \( \text{Direction} = \tan^{-1}\left(\frac{y}{x}\right) \). Let's calculate the magnitude and direction of the vector \( \vec{g} = \langle 9, -7 \rangle \): 1. Calculate the magnitude: \[ \text{Magnitude} = \sqrt{9^2 + (-7)^2} = \sqrt{81 + 49} = \sqrt{130} \] 2. Calculate the direction: \[ \text{Direction} = \tan^{-1}\left(\frac{-7}{9}\right) \] Now, let's calculate the direction in degrees and round it to the nearest tenth of a degree. Calculate the value by following steps: - step0: Calculate: \(\sqrt{130}\) Calculate or simplify the expression \( \tan^{-1}(-7/9) \). Calculate the value by following steps: - step0: Calculate: \(\arctan\left(\frac{-7}{9}\right)\) - step1: Rewrite the fraction: \(\arctan\left(-\frac{7}{9}\right)\) The magnitude of the vector \( \vec{g} = \langle 9, -7 \rangle \) is approximately \( 11.401754 \) and the direction is approximately \( -0.661043 \) radians. To convert the direction from radians to degrees, we can use the conversion factor \( 1 \text{ radian} = \frac{180}{\pi} \text{ degrees} \). \[ \text{Direction in degrees} = -0.661043 \times \frac{180}{\pi} \] Let's calculate the direction in degrees. Calculate the value by following steps: - step0: Calculate: \(-0.661043\times \frac{180}{\pi }\) - step1: Convert the expressions: \(-\frac{661043}{1000000}\times \frac{180}{\pi }\) - step2: Multiply the numbers: \(-\frac{5949387}{50000\pi }\) The direction of the vector \( \vec{g} = \langle 9, -7 \rangle \) in degrees is approximately \( -37.874974 \) degrees. Therefore, the magnitude of the vector \( \vec{g} \) is approximately \( 11.401754 \) and the direction is approximately \( -37.874974 \) degrees.

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To find the magnitude of the vector \(\vec{g} = \langle 9, -7 \rangle\), we use the formula for the magnitude of a vector, which is \(\sqrt{x^2 + y^2}\). Calculating this, we get: \[ \text{Magnitude} = \sqrt{9^2 + (-7)^2} = \sqrt{81 + 49} = \sqrt{130} \] Thus, the magnitude is \(\sqrt{130}\). Now, for the direction (angle \(\theta\)), we use the tangent function: \[ \tan(\theta) = \frac{y}{x} = \frac{-7}{9} \] To find \(\theta\), we compute the arctangent: \[ \theta = \tan^{-1}\left(-\frac{7}{9}\right) \] Calculating this gives: \[ \theta \approx -38.7^\circ \] Since the vector lies in the fourth quadrant, we can find the positive angle by adding \(360^\circ\): \[ \theta \approx 360^\circ - 38.7^\circ \approx 321.3^\circ \] So, the magnitude of \(\vec{g}\) is \(\sqrt{130}\) and the direction is approximately \(321.3^\circ\). When it comes to vectors, historical figures like Galilei and Newton set the stage for understanding motion through vector analysis. While some explorers once risked their lives traversing uncharted territories without precise direction, today, we can navigate easily with vector calculus, showcasing the strides made in knowledge! In practical situations, combining vectors can lead to common mistakes, such as forgetting to consider the signs of the components. Always remember to revert back to your coordinate system: the direction you choose affects both angle and resultant vector significantly, especially in navigation or physics contexts!

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