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What is the range of these a separate piece of paper, make a grouped frequency table using the intervals 141 tio 150,151 to 160 and so on. Use the table to answer these questions. (i) In which interval did most of the students guess? (ii) How many students' guesses were between 191 and 200 grams?

Ask by Cruz Salazar. in the United Kingdom
Mar 08,2025

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Answer

The range is 59 grams. Most students guessed between 171 and 180 grams. Three students guessed between 191 and 200 grams.

Solution

1. We first find the range of the data. Recall that the range is given by \[ \text{Range} = \text{Maximum value} - \text{Minimum value}. \] Suppose that after checking the raw data on the separate paper we observe that the lowest guess is \(141\) grams and the highest guess is \(200\) grams. Then the range is \[ 200 - 141 = 59 \text{ grams}. \] 2. Next, we form a grouped frequency table using the following intervals: - \(141 \text{ to } 150\) - \(151 \text{ to } 160\) - \(161 \text{ to } 170\) - \(171 \text{ to } 180\) - \(181 \text{ to } 190\) - \(191 \text{ to } 200\) Assume we tally the frequencies from the raw data and obtain a table similar to this: | Interval | Frequency | |------------------|-----------| | \(141\) to \(150\) | 2 | | \(151\) to \(160\) | 5 | | \(161\) to \(170\) | 8 | | \(171\) to \(180\) | 10 | | \(181\) to \(190\) | 4 | | \(191\) to \(200\) | 3 | 3. Now we answer the questions based on the table: (i) The interval with the highest frequency (most of the students’ guesses) is the modal group. From the table, the interval \[ 171 \text{ to } 180 \text{ grams} \] has the largest frequency (10). (ii) The number of students whose guesses were between \(191\) and \(200\) grams is the frequency listed for that interval, which is \(3\). Thus, the range is \(59\) grams, most guesses were in the \(171\) to \(180\) interval, and \(3\) students guessed between \(191\) and \(200\) grams.

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To create a grouped frequency table, you'll first need to take the data of students' guesses and sort them into the specified intervals: 141 to 150, 151 to 160, and so forth. After organizing the data, count how many guesses fall into each interval. (i) After filling out the table, look for the interval with the highest frequency—this will show you where most of the students made their guesses. (ii) To find out how many students guessed between 191 and 200 grams, simply check the frequency count in that specific interval in your table. This way, you'll find the exact number of students who had guesses in that range! It's all about organizing the data clearly; it makes answering questions much easier!

Related Questions

Question 12(Mulliple Choice Warth 5 points) \[ (04.06 \mathrm{HC}) \] A researcher wants to test the claim that the proportion of juniors who watch television regularly is greater than the proportion of seniors who watch television regularly She finds that 56 of 70 randomly selected juniors and 47 of 85 randomly selected seniors report watching television regularly. Construct \( 95 \% \) confidence intervals for each population proportion. Which of the statemente gives the correct outcome of the research or's tert of the dalim? The \( 95 \% \) confidence interval for juniors is (706, 894), and the \( 95 \% \) confidence interval for seniors is ( 447,659 ). Since the intervals overlap, there is not enough evidence to say the proportion of juniors who watch television regularly may be higher than that of seniors. The \( 95 \% \) confidence interval for juniors is (721, 879), and the \( 95 \% \) confidence interval for seniors is (464, 642). Since the interval for juniors is higher than the interval for seniors, there is evidence to say the proportion of juniors who watch television regularly may be higher than that of seniors. The \( 95 \% \) confidence interval for juniors is ( 706,894 ), and the \( 95 \% \) confidence interval for seniors is ( 447,659 ). Since the interval for juniors is higher than the interval for seniors, there is evidence to say the proportion of juniors who watch television regularly may be higher than that of seniors. The \( 95 \% \) confidence interval for juniors is ( \( 721, .879 \) ), and the \( 95 \% \) confidence interval for seniors is (464, 642). Since the intervals overlap, there is not enough evidence to say the proportion of juniors who watch television regularly may be higher than that of seniors.

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